这是使用GAE中的持久性来设置和获取字符串值的正确方法吗?
我收到错误:
com.google.appengine.api.datastore.EntityNotFoundException: No entity was found matching the key: jsonString("jsonString")
添加到商店:
DatastoreService datastore = DatastoreServiceFactory.getDatastoreService();
Key key = KeyFactory.createKey("jsonString", "jsonString");
Entity urlEntity = new Entity("jsonString" , key);
urlEntity.setProperty("urlVal", urlVal);
com.google.appengine.api.datastore.Key urlEntityKey = datastore.put(urlEntity);
从商店回来:
Key key = KeyFactory.createKey("jsonString", "jsonString");
DatastoreService datastore = DatastoreServiceFactory.getDatastoreService();
Entity entity = datastore.get(key);
答案 0 :(得分:0)
请查看以下代码,您还可以查看文档here,找到有关如何使用应用引擎数据存储API的更多详细信息。另请查看Datastore Overview文档中的说明。
DatastoreService ds = DatastoreServiceFactory.getDatastoreService();
Entity e = new Entity("data");
e.setProperty("jsonString", "myValue");
Key key = ds.put(e);
Entity entity = ds.get(key);
System .out.println(entity);