虽然网上有一些教程,但我仍然不知道为什么这不能正确打印多个页面。我做错了什么?
public static void printTest()
{
PrintDialog printDialog1 = new PrintDialog();
PrintDocument printDocument1 = new PrintDocument();
printDialog1.Document = printDocument1;
printDocument1.PrintPage +=
new PrintPageEventHandler(printDocument1_PrintPage);
DialogResult result = printDialog1.ShowDialog();
if (result == DialogResult.OK)
{
printDocument1.Print();
}
}
static void printDocument1_PrintPage(object sender, PrintPageEventArgs e)
{
Graphics graphic = e.Graphics;
SolidBrush brush = new SolidBrush(Color.Black);
Font font = new Font("Courier New", 12);
e.PageSettings.PaperSize = new PaperSize("A4", 850, 1100);
float pageWidth = e.PageSettings.PrintableArea.Width;
float pageHeight = e.PageSettings.PrintableArea.Height;
float fontHeight = font.GetHeight();
int startX = 40;
int startY = 30;
int offsetY = 40;
for (int i = 0; i < 100; i++)
{
graphic.DrawString("Line: " + i, font, brush, startX, startY + offsetY);
offsetY += (int)fontHeight;
if (offsetY >= pageHeight)
{
e.HasMorePages = true;
offsetY = 0;
}
else {
e.HasMorePages = false;
}
}
}
您可以在此处找到此代码打印结果的示例:Printed Document
答案 0 :(得分:8)
你永远不会从循环中返回。将其更改为:
if (offsetY >= pageHeight)
{
e.HasMorePages = true;
offsetY = 0;
return; // you need to return, then it will go into this function again
}
else {
e.HasMorePages = false;
}
此外,您需要将循环更改为从第2页上的当前编号开始,而不是再次使用i = 0重新启动。