好的,我得到的是两个型号......
Jiraissue:
class Jiraissue < ActiveRecord::Base
# JIRA uses a singular table name for this model
set_table_name 'jiraissue'
has_one :severity
end
严重性:
class Severity < ActiveRecord::Base
belongs_to :jiraissue
end
我要做的是得到jiraissue.severity =“S1”的所有Jiraissues的数量
现在事实证明jiraissue表有一个优先级列,所以我可以在模型中提取这个技巧......
Jiraissue:
class Jiraissue < ActiveRecord::Base
# JIRA uses a singular table name for this model
set_table_name 'jiraissue'
has_one :severity
def self.count_priority(priority)
where("PRIORITY = ?",priority).count()
end
end
然后在视图中执行类似......
的操作<%= (1..4).map {
|priority| Jiraissue.biit.bugs.recent.count_priority(priority)
}.inspect %>
如何为Jiraissue做类似的事情来获取count_severity方法?
这不起作用(我也不期望)......
def self.count_severity(severity)
where("severity = ?",severity).count()
end
但我完全糊涂了。
答案 0 :(得分:0)
Jiraissue.joins(:severities).where(:severities => {:severity => "S1"}).count
答案 1 :(得分:0)
<强>模型强>
def self.count_priority(priority)
where("PRIORITY = ?",priority).size
end
<强>控制器强>
def index
@jiraissues = Jiraissue.count_priority('S1')
end
不起作用吗?