我遇到了一些搜索代码问题。我有一个名为searchedData
的NSMutableArray,它包含NSDictionaries(每个对象一个)。这是我现在的搜索代码:
- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
{
[tableData removeAllObjects]; // remove all data that belongs to previous search
if([searchText isEqualToString:@""]||searchText==nil) {
[tableView reloadData];
return;
}
int i = 0;
while (i < [dataSource count]) {
NSDictionary *coolDict = [searchedData objectAtIndex:i];
NSString * title = [coolDict objectForKey:@"TITLE"];
NSString * authorString = [coolDict objectForKey:@"AUTHOR"];
NSRange titleRange = [[title lowercaseString] rangeOfString:[searchText lowercaseString]];
NSRange authorRange = [[authorString lowercaseString] rangeOfString:[searchText lowercaseString]];
if (titleRange.location != NSNotFound || authorRange.location != NSNotFound)
[tableData addObject:title];
i++;
}
[tableView reloadData];
}
找到条目数,然后转到每个条目,找到键“TITLE”和“AUTHOR”的对象,然后在匹配的情况下在UITableView中显示条目。
问题在于它永远不会显示任何内容,即使匹配也是如此。 我知道表/字典不是null(我有NSLogged它)所以我不知道为什么它不起作用。
答案 0 :(得分:4)
您忘记重新加载已将相关数据添加到数据源的tableView。
我稍微改进了方法的编码,并添加了缺失的行。
- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
{
[tableData removeAllObjects];// remove all data that belongs to previous search
if (![searchText isEqualToString:@""] || searchText != nil) {
int i = 0;
while (i < [dataSource count]) {
NSDictionary *coolDict = [searchedData objectAtIndex:i];
NSString * title = [coolDict objectForKey:@"TITLE"];
NSString * authorString = [coolDict objectForKey:@"AUTHOR"];
NSRange titleRange = [[title lowercaseString] rangeOfString:[searchText lowercaseString]];
NSRange authorRange = [[authorString lowercaseString] rangeOfString:[searchText lowercaseString]];
if(titleRange.location != NSNotFound || authorRange.location != NSNotFound)
[tableData addObject:title];
i++;
}
}
[tableView reloadData];
}