我是liferay门户网站的新手。我在liferay中开发了一个用于演示的portlet。我在这个例子中使用了port portlet通信。我正在做的是: - 我有一个搜索portlet,其中我有一个文本字段用于搜索。当我点击搜索按钮时,它从数据库中获取数据并使用另一个portlet中包含的搜索显示该数据。我为这个项目使用了ProcessEvent和ActionEvent注释。
现在我想要的是当我点击搜索按钮然后页面不应该刷新(即我希望使用AJAX的概念)并且数据应该显示在另一个portlet上。
代码段
Portlet A - view.jsp
<%@include file="/html/init.jsp"%>
<portlet:defineObjects />
<!--
<portlet:actionURL var="actionURL" name="pitchBall"></portlet:actionURL>
//-->
**Change to Resource URL**
<portlet:resourceURL var="resourceURL">
</portlet:resourceURL>
<aui:form method="POST" action="<%= resourceURL%>" name=" <portlet:namespace>fm1</portlet:namespace>">
<aui:input name="search" id="search" />
<aui:button type="submit" name="Search" value="Search" />
</aui:form>
Portlet A - SearchPortlet类
package com.test;
/**
* Portlet implementation class SearchPortlet
*/
public class SearchPortlet extends GenericPortlet {
@Override
public void render(RenderRequest request, RenderResponse response)
throws PortletException, IOException {
// TODO Auto-generated method stub
super.render(request, response);
}
@ProcessAction(name="pitchBall")
public void pitchBall(ActionRequest request, ActionResponse response) throws SystemException {
String name = ParamUtil.getString(request, "search");
QName qName = new QName("http://liferay.com/events", "ipc.pitch");
response.setEvent(qName, name);
}
public void init() {
editJSP = getInitParameter("edit-jsp");
helpJSP = getInitParameter("help-jsp");
viewJSP = getInitParameter("view-jsp");
}
public void doEdit(
RenderRequest renderRequest, RenderResponse renderResponse)
throws IOException, PortletException {
include(editJSP, renderRequest, renderResponse);
}
public void doHelp(
RenderRequest renderRequest, RenderResponse renderResponse)
throws IOException, PortletException {
include(helpJSP, renderRequest, renderResponse);
}
@Override
public void doView(
RenderRequest renderRequest, RenderResponse renderResponse)
throws IOException, PortletException {
//super.doView(renderRequest, renderResponse);
System.out.println("In doView code");
renderResponse.setContentType(renderRequest.getResponseContentType());
// file to display...
String url = "/html/searchportlet/view.jsp";
// read the above file and output it...
getPortletContext().getRequestDispatcher(url).include(renderRequest, renderResponse);
//include(viewJSP, renderRequest, renderResponse);
}
@Override
public void serveResource(ResourceRequest request, ResourceResponse response)
throws PortletException, IOException {
// TODO Auto-generated method stub
//super.serveResource(request, response);
System.out.println("In serveResource code");
response.setContentType("text/html");
String name = request.getParameter("search");
// this seems to be the page that was calling...?
String resourceID = request.getResourceID();
System.out.println("resourceId was : " + resourceID);
System.out.println("message was : " + name);
PrintWriter writer = response.getWriter();
writer.print(name);
}
protected void include(
String path, RenderRequest renderRequest,
RenderResponse renderResponse)
throws IOException, PortletException {
PortletRequestDispatcher portletRequestDispatcher =
getPortletContext().getRequestDispatcher(path);
if (portletRequestDispatcher == null) {
_log.error(path + " is not a valid include");
}
else {
portletRequestDispatcher.include(renderRequest, renderResponse);
}
}
protected String editJSP;
protected String helpJSP;
protected String viewJSP;
private static Log _log = LogFactoryUtil.getLog(SearchPortlet.class);
}
Portlet B - view.jsp
<%@include file="/html/init.jsp"%>
<portlet:defineObjects />
<%
String name = (String)renderRequest.getParameter("name");
%>
<liferay-ui:search-container
emptyResultsMessage="author-empty-results-message">
<liferay-ui:search-container-results
results="<%= KeyurAuthorLocalServiceUtil.getStudentByName(name) %>" />
<liferay-ui:search-container-row className="com.test.model.KeyurAuthor">
<liferay-ui:search-container-column-text name="authorId"
property="authorId" />
<liferay-ui:search-container-column-text name="authorName"
property="authorName" />
<liferay-ui:search-container-column-text name="authorEmail"
property="authorEmail" />
</liferay-ui:search-container-row>
<liferay-ui:search-iterator></liferay-ui:search-iterator>
</liferay-ui:search-container>
Portlet B - SearchResultPortlet类
/**
* Portlet implementation class SearchResultPortlet
*/
public class SearchResultPortlet extends GenericPortlet {
public void init() {
editJSP = getInitParameter("edit-jsp");
helpJSP = getInitParameter("help-jsp");
viewJSP = getInitParameter("view-jsp");
}
@ProcessEvent(qname="{http://liferay.com/events}ipc.pitch")
public void catchBall(EventRequest request, EventResponse response) {
Event event = request.getEvent();
String name = (String)event.getValue();
response.setRenderParameter("name", name);
}
public void doEdit(
RenderRequest renderRequest, RenderResponse renderResponse)
throws IOException, PortletException {
include(editJSP, renderRequest, renderResponse);
}
public void doHelp(
RenderRequest renderRequest, RenderResponse renderResponse)
throws IOException, PortletException {
include(helpJSP, renderRequest, renderResponse);
}
public void doView(
RenderRequest renderRequest, RenderResponse renderResponse)
throws IOException, PortletException {
include(viewJSP, renderRequest, renderResponse);
}
protected void include(
String path, RenderRequest renderRequest,
RenderResponse renderResponse)
throws IOException, PortletException {
PortletRequestDispatcher portletRequestDispatcher =
getPortletContext().getRequestDispatcher(path);
if (portletRequestDispatcher == null) {
_log.error(path + " is not a valid include");
}
else {
portletRequestDispatcher.include(renderRequest, renderResponse);
}
}
protected String editJSP;
protected String helpJSP;
protected String viewJSP;
private static Log _log = LogFactoryUtil.getLog(SearchResultPortlet.class);
}
答案 0 :(得分:18)
在门户网站上发出ajax请求时,你的portlet应该实现
javax.portlet.ResourceServingPortlet
GenericPortlet已经执行了但你想要覆盖它,而不是使用<portlet:actionURL />
,你应该从行动中使用<portlet:resourceURL />
。
在您的设置中,您应该有关键字的隐藏字段的搜索表单,并且在搜索portlet中单击提交按钮时,您应该使用IPC将该表单中的关键字复制到搜索结果portlet并从搜索结果调用提交(不包括在搜索portlet(A)中提交表单。
您的SearchResultPortlet类应为
public class SearchResultPortlet extends GenericPortlet {
...
public void serveResource(ResourceRequest request, ResourceResponse response) throws PortletException, java.io.IOException {
// do search and return result
}
...
}
编辑:完整示例
SearchForm
import java.io.IOException;
import javax.portlet.GenericPortlet;
import javax.portlet.PortletException;
import javax.portlet.RenderRequest;
import javax.portlet.RenderResponse;
public class SearchForm extends GenericPortlet {
@Override
protected void doView(RenderRequest p_request, RenderResponse p_response) throws PortletException, IOException {
getPortletContext().getRequestDispatcher("/WEB-INF/jsp/search.jsp").include(p_request, p_response);
}
}
信息搜索结果
import java.io.IOException;
import javax.portlet.GenericPortlet;
import javax.portlet.PortletException;
import javax.portlet.RenderRequest;
import javax.portlet.RenderResponse;
import javax.portlet.ResourceRequest;
import javax.portlet.ResourceResponse;
public class SearchResult extends GenericPortlet {
@Override
protected void doView(RenderRequest p_request, RenderResponse p_response) throws PortletException, IOException {
getPortletContext().getRequestDispatcher("/WEB-INF/jsp/result.jsp").include(p_request, p_response);
}
@Override
public void serveResource(ResourceRequest p_request, ResourceResponse p_response) throws PortletException, IOException {
//do your search here and put results in 'result'
p_request.setAttribute("result", "results for: " + p_request.getParameter("search"));
getPortletContext().getRequestDispatcher("/WEB-INF/jsp/html.jsp").include(p_request, p_response);
}
}
search.jsp的
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
<%@ taglib uri="http://java.sun.com/portlet" prefix="portlet" %>
<portlet:defineObjects />
<script type="text/javascript">
function doSearch() {
Liferay.fire('searchKeywords', document.getElementById("<portlet:namespace/>search").value);
}
</script>
<form>
<input type="text" name="search" id="<portlet:namespace/>search" />
<button name="Search" value="Search" onclick="doSearch()" type="button">Search</button>
</form>
result.jsp中
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
<%@ taglib uri="http://java.sun.com/portlet" prefix="portlet" %>
<%@ taglib uri="http://liferay.com/tld/aui" prefix="aui" %>
<portlet:defineObjects />
<portlet:resourceURL var="rurl" />
<script type="text/javascript">
Liferay.on('searchKeywords', function(event, p_data){
var A = AUI();
A.use('aui-io-request', function(aui) {
A.io.request("<%= rurl %>", {
method : 'POST',
data: {search: p_data},
dataType : 'html',
on : {
success : function() {
AUI().one("#<portlet:namespace/>placeholder").html(this.get('responseData'));
}
}
});
});
});
</script>
Search Results:<br />
<div id="<portlet:namespace/>placeholder">
</div>
html.jsp(这是为了渲染结果)
<%= request.getAttribute("result") %>
答案 1 :(得分:1)
您可以在客户端使用Inter portlet通信。 让我们将portletA称为搜索portlet,将portletB称为另一个portlet中包含的搜索。 我假设你正在使用Liferay 6 +。
第1步:点击portletA上的搜索按钮将触发浏览器上的以下javascript功能:
var A = AUI();
A.use('aui-io-request',
function(aui) {
A.io.request(<portletA_serch_action_url>, {
method : 'GET',
dataType : 'json',
on : {
success : function() {
Liferay.fire('myEvent', this.get('responseData');
}
}
});
}
);
请注意A.io.request(<portletA_serch_action_url>...
的来电
这是portletA服务器端操作URL。
有关Liferay 6和ajax的更多信息,请参阅以下Liferay博客:http://www.liferay.com/web/nathan.cavanaugh/blog/-/blogs/alloyui-working-with-ajax。
步骤2 :对于portletA服务器响应,portletA客户端将启动一个事件,其中包含从服务器检索到的数据。
请注意对Liferay.fire('myEvent', this.get('responseData');
的调用,这是Liferay在客户端支持客户端Inter Portlet通信的方式(参见http://www.liferay.com/community/wiki/-/wiki/Main/Client-side+Inter-Portlet+Communication)。
myEvent
是被触发的事件,this.get('responseData');
是从服务器检索的数据。
第3步:客户端portletB侦听myEvent并呈现数据
portletB将侦听myEvent,然后呈现数据:
Liferay.on(
'myEvent',
function(event, data){
var portletId = data.portletId;
var portlet = data.portlet;
if(portletId.indexOf('YOUR_PORTLET_A_ID') > -1){
alert(data);
}
}
);
请注意检查portletA中数据的来源:
if(portletId.indexOf('YOUR_PORTLET_A_ID') > -1){...
如果您没有其他portlet触发同一事件,则可以删除该检查。
希望得到这个帮助。
答案 2 :(得分:0)
---------------------------jsp代码------------------- -
<portlet:resourceURL var="testAjaxResourceUrl"></portlet:resourceURL>
<form id="testAjaxForm" action="">
<input type="text" name="<portlet:namespace />param2">
<input type="button" value="Submit" onclick="ajaxCall()">
</form>
<script type="text/javascript">
function ajaxCall(){
AUI().use('aui-base', 'io', 'aui-io-request', function(A){
A.io.request('${testAjaxResourceUrl}', {
method: 'post',
data: {
<portlet:namespace />sampleParam: 'value2',
},
form:{
id:'testAjaxForm'
},
on: {
success: function() {
alert(this.get('responseData'));
}
}
});
});
}
</script>
--------------java 代码-------------- ------
@Override
public void serveResource(ResourceRequest resourceRequest, ResourceResponse resourceResponse)
throws IOException, PortletException {
String param = ParamUtil.getString(resourceRequest, "param2");
System.out.println("Parameter is ==>" + param);
resourceResponse.setContentType("text/html");
PrintWriter out = resourceResponse.getWriter();
out.print("You have entered ==>"+param);
System.out.println("Ajax call is performed");
out.flush();
super.serveResource(resourceRequest, resourceResponse);
}