如何将timeval转换为time_t?我正在尝试转换: umtp-> ut_tv到time_t所以我可以使用difftime(a,b)。
struct {
int32_t tv_sec; /* Seconds */
int32_t tv_usec; /* Microseconds */
} ut_tv; /* Time entry was made */
struct timeval ut_tv; /* Time entry was made */
答案 0 :(得分:9)
time_t
只存储秒数,所以
time_t time = (time_t)ut_tv.tv_sec;
应该有效,但由于你只是在寻找差异,所以总有减法的魔力。
struct timeval diff = {a.tv_sec-b.tv_sec, a.tv_usec-b.tv_usec};
这使您可以保持以前的所有精确度。
答案 1 :(得分:2)
不使用c-cast,您只需执行此操作:
struct timeval rawtime_s_us;
gettimeofday( &rawtime_s_us, NULL );
time_t rawtime_s = rawtime_s_us.tv_sec;