Question

我发现以下方式进行十六进制到二进制转换：

String binAddr = Integer.toBinaryString(Integer.parseInt(hexAddr, 16));

虽然此方法适用于小十六进制数，但十六进制数如下

A14AA1DBDB818F9759

引发NumberFormatException.

因此，我编写了以下似乎有效的方法：

private String hexToBin(String hex){
    String bin = "";
    String binFragment = "";
    int iHex;
    hex = hex.trim();
    hex = hex.replaceFirst("0x", "");

    for(int i = 0; i < hex.length(); i++){
        iHex = Integer.parseInt(""+hex.charAt(i),16);
        binFragment = Integer.toBinaryString(iHex);

        while(binFragment.length() < 4){
            binFragment = "0" + binFragment;
        }
        bin += binFragment;
    }
    return bin;
}

上面的方法基本上取十六进制字符串中的每个字符并将其转换为二进制等效值，如果需要，用零填充它，然后将其连接到返回值。这是执行转换的正确方法吗？或者我是否忽略了可能导致我失败的方法？

提前感谢您的任何帮助。

Answer 1

BigInteger.toString(radix)会做你想要的。只需输入2的基数。

static String hexToBin(String s) {
  return new BigInteger(s, 16).toString(2);
}

Answer 2

Integer.parseInt(hex,16);    
System.out.print(Integer.toBinaryString(hex));

将十六进制（String）解析为带有基数16的整数，然后使用toBinaryString（int）方法将其转换为二进制字符串

例如

int num = (Integer.parseInt("A2B", 16));
System.out.print(Integer.toBinaryString(num));

将打印

101000101011

由int处理的Max Hex vakue是FFFFFFF

即。如果传递FFFFFFF0，则会给出错误

Answer 3

全部为零：

static String hexToBin(String s) {
    String preBin = new BigInteger(s, 16).toString(2);
    Integer length = preBin.length();
    if (length < 8) {
        for (int i = 0; i < 8 - length; i++) {
            preBin = "0" + preBin;
        }
    }
    return preBin;
}

Answer 4

public static byte[] hexToBin(String str)
    {
        int len = str.length();
        byte[] out = new byte[len / 2];
        int endIndx;

        for (int i = 0; i < len; i = i + 2)
        {
            endIndx = i + 2;
            if (endIndx > len)
                endIndx = len - 1;
            out[i / 2] = (byte) Integer.parseInt(str.substring(i, endIndx), 16);
        }
        return out;
    }

Answer 5

import java.util.*;
public class HexadeciamlToBinary
{
   public static void main()
   {
       Scanner sc=new Scanner(System.in);
       System.out.println("enter the hexadecimal number");
       String s=sc.nextLine();
       String p="";
       long n=0;
       int c=0;
       for(int i=s.length()-1;i>=0;i--)
       {
          if(s.charAt(i)=='A')
          {
             n=n+(long)(Math.pow(16,c)*10);
             c++;
          }
         else if(s.charAt(i)=='B')
         {
            n=n+(long)(Math.pow(16,c)*11);
            c++;
         }
        else if(s.charAt(i)=='C')
        {
            n=n+(long)(Math.pow(16,c)*12);
            c++;
        }
        else if(s.charAt(i)=='D')
        {
           n=n+(long)(Math.pow(16,c)*13);
           c++;
        }
        else if(s.charAt(i)=='E')
        {
            n=n+(long)(Math.pow(16,c)*14);
            c++;
        }
        else if(s.charAt(i)=='F')
        {
            n=n+(long)(Math.pow(16,c)*15);
            c++;
        }
        else
        {
            n=n+(long)Math.pow(16,c)*(long)s.charAt(i);
            c++;
        }
    }
    String s1="",k="";
    if(n>1)
    {
    while(n>0)
    {
        if(n%2==0)
        {
            k=k+"0";
            n=n/2;
        }
        else
        {
            k=k+"1";
            n=n/2;
        }
    }
    for(int i=0;i<k.length();i++)
    {
        s1=k.charAt(i)+s1;
    }
    System.out.println("The respective binary number is : "+s1);
    }
    else
    {
        System.out.println("The respective binary number is : "+n);
    }
  }
}

Answer 6

快速，适用于大字符串：

    private String hexToBin(String hex){
        hex = hex.replaceAll("0", "0000");
        hex = hex.replaceAll("1", "0001");
        hex = hex.replaceAll("2", "0010");
        hex = hex.replaceAll("3", "0011");
        hex = hex.replaceAll("4", "0100");
        hex = hex.replaceAll("5", "0101");
        hex = hex.replaceAll("6", "0110");
        hex = hex.replaceAll("7", "0111");
        hex = hex.replaceAll("8", "1000");
        hex = hex.replaceAll("9", "1001");
        hex = hex.replaceAll("A", "1010");
        hex = hex.replaceAll("B", "1011");
        hex = hex.replaceAll("C", "1100");
        hex = hex.replaceAll("D", "1101");
        hex = hex.replaceAll("E", "1110");
        hex = hex.replaceAll("F", "1111");
        return hex;
    }

Answer 7

public static byte[] hexToBytes(String string) {
 int length = string.length();
 byte[] data = new byte[length / 2];
 for (int i = 0; i < length; i += 2) {
  data[i / 2] = (byte)((Character.digit(string.charAt(i), 16) << 4) + Character.digit(string.charAt(i + 1), 16));
 }
 return data;
}

将十六进制字符串（十六进制）转换为二进制字符串

7 个答案: