Question

可能重复：
except condition in mysql query..

考虑一个名为carrecords的表，其结构如下：

名称（类型：TEXT）价格（类型：INT）颜色（类型：TEXT） vehicletype（类型：TEXT）例如。 SEDAN / SUV

客户希望查看符合其偏好的车辆的详细信息（名称，价格，颜色，车型）。这就是他所说的：

“如果它是黑色轿车，我准备支付10,000，但如果是红色或白色，那么不超过8,000。对于任何其他颜色，我不会超过7,000，除非它是一辆SUV，在哪种情况下，黑色的预算高达15,000或任何其他颜色高达14,000。“

编写一个查询，按价格的升序返回所需信息。

我的解决方案如下。

SELECT *
FROM carrecords
WHERE name='SEDAN' 
     AND  color='black'
     AND price=10000
UNION
SELECT *
FROM carrecords
WHERE name='SEDAN'
      AND color='RED' OR color='WHITE'
      AND price<=8000
UNION
SELECT * 
FROM carrecords
WHERE name='SEDAN'
     AND color!='BLACK'
     AND price<=7000
UNION
SELECT *
FROM carrecords
WHERE name='SUV'
      AND color='BLACK'
      AND price<=15000
UNION
SELECT * 
FROM carrecords
WHERE name='SUV'
     AND color!='BLACK'
     AND price<=14000
ORDER BY price;

Answer 1

我认为值'SUV'和'SEDAN'在'type'列中，而不在'name'列中。另外，你可以像这样简洁地写出来：

SELECT *
FROM carrecords
WHERE (type='SEDAN' 
     AND ((color='BLACK'
          AND price<=10000)
     OR (color IN ('RED', 'WHITE')
          AND price<=8000)
     OR (color NOT IN ('BLACK', 'RED', 'WHITE')
          AND price<=7000)))
     OR
     (type='SUV' 
     AND ((color='BLACK'
          AND price<=15000)
     OR (color != 'BLACK'
         AND price<=14000))
ORDER BY price

Answer 2

实际上，你可以在没有联盟的情况下做到这一点：

Select * from carrecords
where (type='Sudan' AND price <= 7000) 
OR (type='Sudan' and color in ('Red','White') and price <= 8000) 
OR (type='Sudan' AND color = 'Black' AND price <= 10000)
OR (type='SUV' and price <=14000)
OR (type='SUV' and color='Black' and price <=15000)
order by price

使用ELANCE中的UNION运算符的SQL

2 个答案: