SQL Server 2008 - 高级搜索/排序

Question

我需要对列进行搜索并按特定顺序对结果进行排序。搜索条件和排序顺序如下：

必须匹配给定搜索文本的至少“x”和最多所有字符。结果应按开头分组（然后按匹配的字符数排序），然后按包含（然后按匹配的字符数和字母顺序排序）。

例如：

搜索文字：联盟A

数据库中的值：

搜索结果应按以下顺序显示

有人可以帮帮我吗？

Answer 1

您正在寻找Levenshtein distance

这是T-SQL的算法实现：Calculating Levenshtein Distance in TSQL

由于功能签名如下：

CREATE FUNCTION [dbo].[LEVENSHTEIN]( @s NVARCHAR(MAX), @t NVARCHAR(MAX) )
/*
Levenshtein Distance Algorithm: TSQL Implementation
by Joseph Gama

http://www.merriampark.com/ldtsql.htm

您可以在查询中将其调用为：

Select *
from ValuesInDatabase V
order by
    [dbo].[LEVENSHTEIN](  V.ClientName, 'Alliance A' ) 

你不应该期待高性能。

<强>被修改

我在这里复制约瑟夫·加马保留它的功能，不要忘记访问devioblog：

CREATE FUNCTION [dbo].[LEVENSHTEIN]( @s NVARCHAR(MAX), @t NVARCHAR(MAX) )
/*
Levenshtein Distance Algorithm: TSQL Implementation
by Joseph Gama

http://www.merriampark.com/ldtsql.htm

Returns the Levenshtein Distance between strings s1 and s2.
Original developer: Michael Gilleland http://www.merriampark.com/ld.htm
Translated to TSQL by Joseph Gama

Fixed by Herbert Oppolzer / devio
as described in http://devio.wordpress.com/2010/09/07/calculating-levenshtein-distance-in-tsql
*/
RETURNS INT AS
BEGIN
  DECLARE @d NVARCHAR(MAX), @LD INT, @m INT, @n INT, @i INT, @j INT,
    @s_i NCHAR(1), @t_j NCHAR(1),@cost INT

  --Step 1
  SET @n = LEN(@s)
  SET @m = LEN(@t)
  SET @d = REPLICATE(NCHAR(0),(@n+1)*(@m+1))
  IF @n = 0
  BEGIN
    SET @LD = @m
   GOTO done
  END
  IF @m = 0
  BEGIN
    SET @LD = @n
    GOTO done
  END

  --Step 2
  SET @i = 0
  WHILE @i <= @n BEGIN
    SET @d = STUFF(@d,@i+1,1,NCHAR(@i))        --d(i, 0) = i
    SET @i = @i+1
  END

  SET @i = 0
  WHILE @i <= @m BEGIN
    SET @d = STUFF(@d,@i*(@n+1)+1,1,NCHAR(@i))    --d(0, j) = j
    SET @i = @i+1
  END

  --Step 3
  SET @i = 1
  WHILE @i <= @n BEGIN
    SET @s_i = SUBSTRING(@s,@i,1)

    --Step 4
    SET @j = 1
    WHILE @j <= @m BEGIN
      SET @t_j = SUBSTRING(@t,@j,1)
      --Step 5
      IF @s_i = @t_j
        SET @cost = 0
      ELSE
        SET @cost = 1
      --Step 6
      SET @d = STUFF(@d,@j*(@n+1)+@i+1,1,
        NCHAR(dbo.MIN3(
          UNICODE(SUBSTRING(@d,@j*(@n+1)+@i-1+1,1))+1,
          UNICODE(SUBSTRING(@d,(@j-1)*(@n+1)+@i+1,1))+1,
          UNICODE(SUBSTRING(@d,(@j-1)*(@n+1)+@i-1+1,1))+@cost)
        ))
      SET @j = @j+1
    END
    SET @i = @i+1
  END      

  --Step 7
  SET @LD = UNICODE(SUBSTRING(@d,@n*(@m+1)+@m+1,1))

done:
  RETURN @LD
END