Question

我必须做一些完全错误的事情，但我无法弄清楚。我有一个表单，我在VS中添加了一个计时器控件。我还有一个正在监视应用程序启动的类（notepad.exe）。当事件到达时，它应该启用计时器，设置间隔并在每个刻度上执行某些操作（例如触发消息框或更改标签）。这似乎没有发生。看看代码可以帮助别人给我一些线索。代码如下：

public partial class Monitor : Form
{
    EventWatcher eventWatch = new EventWatcher();
    ManagementEventWatcher startWatcher = new ManagementEventWatcher();
    ManagementEventWatcher endWatcher = new ManagementEventWatcher();


    public Monitor()
    {
        InitializeComponent();
        startWatcher  = eventWatch.WatchForProcessStart("notepad.exe");
        endWatcher =   eventWatch.WatchForProcessEnd("notepad.exe");
    }

    private void appTimer_Tick(object sender, EventArgs e)
    {
        label1.Text = "tick";
        MessageBox.Show("Tick");
    }

}

守望者班是

class EventWatcher
{

    public ManagementEventWatcher WatchForProcessStart(string processName)
    {
        string queryString =
            "SELECT TargetInstance" +
            "  FROM __InstanceCreationEvent " +
            "WITHIN  2 " +
            " WHERE TargetInstance ISA 'Win32_Process' " +
            "   AND TargetInstance.Name = '" + processName + "'";

        // The dot in the scope means use the current machine
        string scope = @"\\.\root\CIMV2";

        // Create a watcher and listen for events
        ManagementEventWatcher watcher = new ManagementEventWatcher(scope, queryString);
        watcher.EventArrived += ProcessStarted;
        watcher.Start();
        return watcher;
    }


    public void ProcessStarted(object sender, EventArrivedEventArgs e)
    {
       Monitor monitor = new Monitor();
       //set timer interval and start time for Monitor class. (form)
       monitor.appTimer.Interval = 5000;
       monitor.appTimer.Enabled = true;

       MessageBox.Show("notepad started");


    }
}

我注意到两件事：

当notepad.exe启动并且MessageBox.Show("notpad started");行注释掉时，计时器刻度事件中的messabox将不会触发。如果它如上所示，它将显示两个消息框（记事本开始和勾选）。但是，label1.Text无论如何都不会改变。

我不确定我做错了什么。我确信它与如何处理计时器事件有关，但我不确定我应该做什么。有什么想法吗？

Answer 1

您的代码会创建一个新的Monitor实例。因此，您不会访问名为eventWatch.WaitForProcessStart（）的Monitor实例的属性，因此它们不会更改。解决此问题的一种方法是在触发ProcessStarted（）时触发事件。您的代码可能如下所示：

class EventWatcher
{

    public event EventHandler<EventArrivedEventArgs> ProcessStarted;

    public ManagementEventWatcher WatchForProcessStart(string processName)
    {
        string queryString =
            "SELECT TargetInstance" +
            "  FROM __InstanceCreationEvent " +
            "WITHIN  2 " +
            " WHERE TargetInstance ISA 'Win32_Process' " +
            "   AND TargetInstance.Name = '" + processName + "'";

        // The dot in the scope means use the current machine
        string scope = @"\\.\root\CIMV2";

        // Create a watcher and listen for events
        ManagementEventWatcher watcher = new ManagementEventWatcher(scope, queryString);
        watcher.EventArrived += OnProcessStarted;
        watcher.Start();
        return watcher;
    }


    protected virtual void OnProcessStarted(object sender, EventArrivedEventArgs e)
    {

        EventHandler<EventArrivedEventArgs> copy = ProcessStarted;
        if (copy != null)
            copy(sender, e); // fire the event

    }
}

public partial class Monitor : Form
{
    EventWatcher eventWatch = new EventWatcher();
    ManagementEventWatcher startWatcher = new ManagementEventWatcher();
    ManagementEventWatcher endWatcher = new ManagementEventWatcher();


    public Monitor()
    {
        InitializeComponent();
        startWatcher  = eventWatch.WatchForProcessStart("notepad.exe");
        startWatcher.ProcessStarted += startWatcher_ProcessStarted; // subscribe to the event
        endWatcher =   eventWatch.WatchForProcessEnd("notepad.exe");
    }

    private void startWatcher_ProcessStarted(object sender, EventArrivedEventArgs e)
    { 
        Monitor monitor = new Monitor();
        //set timer interval and start time for Monitor class. (form)
        monitor.appTimer.Interval = 5000;
        monitor.appTimer.Enabled = true;

        MessageBox.Show("notepad started");
    }

    private void appTimer_Tick(object sender, EventArgs e)
    {
        label1.Text = "tick";
        MessageBox.Show("Tick");
    }

}

Answer 2

当您从另一个线程运行时，label1.Text看起来也不会改变。您需要在该标签上运行调用以从ManagementEventWatcher更新它。

使用此课程：

using System;
using System.Windows.Forms;

public static class ControlExtensions
{
    /// <summary> 
    /// Executes the Action asynchronously on the UI thread, does not block execution on the calling thread. 
    /// </summary> 
    /// <param name="control"></param> 
    /// <param name="code"></param> 
    public static void UIThread(this Control @this, Action code)
    {
        if (@this.InvokeRequired)
        {
            @this.BeginInvoke(code);
        }
        else
        {
            code.Invoke();
        }
    }
}

and replace `label1.Text = "tick" ` with

this.UIThread(() => this.label1.Text = "tick"));

在另一个类中启用计时器后调用Timer Tick事件

2 个答案: