将数据数组添加到表格中时出现问题。 firebug中没有显示错误消息,并且数据未使用$("#tbNames tr:last").after("<tr><td>" + data[0] + "</td><td>" + data[2] + "</td><td><img src='delete.gif' class='delete' height='15' /></td></tr>");
作为行添加到表中。
逻辑(Javascript)
<script type="text/javascript">
var data = [];
data.push("Coco", "Mandy");
data.push("Suzze", "Candy");
data.push("Janny", "Jacky");
$(document).ready(function() {
$('#btnAdd').live('click', function() {
var name = $('#txtName').val();
var name2 = $('#txtName2').val();
$("#tbNames tr:last").after("<tr><td>" + name + "</td><td>" + name2 + "</td><td><img src='delete.gif' class='delete' height='15' /></td></tr>");
});
$('#tbNames td img.delete').live('click', function() {
$(this).parent().parent().remove();
});
$("#insert_data").click(function() {
for(var i=0; i<data.length; i++){
$("#tbNames tr:last").after("<tr><td>" + data[0] + "</td><td>" + data[2] + "</td><td><img src='delete.gif' class='delete' height='15' /></td></tr>");
}
});
});
</script>
HTML表单
<input id="txtName" type="text" />
<input id="txtName2" type="text" />
<input id="btnAdd" type="button" value="Add" />
<table id="tbNames" border="1" >
<tr>
<th>Name</b></th>
<th>Name2</b></th>
<th>Delete</b></th>
</tr>
<tr>
<td>Bingo</td>
<td>Tingo</td>
<td><img src="Delete.gif" height="15" class="delete" /></td>
</tr>
</table>
<input id="insert_data" type="button" style="height: 35px; width: 225px" value="Retrieve Default User" />
请告知我是否遗漏了任何东西。感谢。
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错误1
更改
data.push("Coco", "Mandy");
data.push("Suzze", "Candy");
data.push("Janny", "Jacky");
到
data.push(["Coco", "Mandy"]);
data.push(["Suzze", "Candy"]);
data.push(["Janny", "Jacky"]);
错误2
更改
$("#insert_data").click(function() {
for(var i=0; i<data.length; i++){
$("#tbNames tr:last").after("<tr><td>" + data[0] + "</td><td>" + data[2] + "</td><td><img src='delete.gif' class='delete' height='15' /></td></tr>");
}
});
到
$("#insert_data").click(function() {
for(var i=0; i<data.length; i++){
$("#tbNames tr:last").after("<tr><td>" + data[i][0] + "</td><td>" + data[i][1] + "</td><td><img src='delete.gif' class='delete' height='15' /></td></tr>");
}
});
答案 0 :(得分:3)
数据数组包含:['Coco','Mandy','Suze','Candy','Janny','Jacky']
所以,目前你的代码产生了:
<tr><td>Coco</td><td>Suzze</td><td><img ...etc></td></tr>
<tr><td>Coco</td><td>Suzze</td><td><img ...etc></td></tr>
<tr><td>Coco</td><td>Suzze</td><td><img ...etc
你的意思是写:
$("#insert_data").click(function() {
for(var i=0; i<data.length-1; i=i+2){
$("#tbNames tr:last").after("<tr><td>" + data[i] + "</td><td>" + data[i+1] + "</td><td><img src='delete.gif' class='delete' height='15' /></td></tr>");
}
});
答案 1 :(得分:2)
这是您的解决方案。发现差异:)。
$(document).ready(function() {
var data = [];
data.push("Coco", "Mandy");
data.push("Suzze", "Candy");
data.push("Janny", "Jacky");
$(document).ready(function() {
$('#btnAdd').live('click', function() {
var name = $('#txtName').val();
var name2 = $('#txtName2').val();
$("#tbNames tr:last").after("<tr><td>" + name + "</td><td>" + name2 + "</td><td><img src='delete.gif' class='delete' height='15' /></td></tr>");
});
$('#tbNames td img.delete').live('click', function() {
$(this).parent().parent().remove();
});
$("#insert_data").click(function() {
for (var i = 0; i < data.length; i++) {
$("#tbNames tr:last").after("<tr><td>" + data[i++]
+ "</td><td>" + data[i]
+ "</td><td><img src='delete.gif' class='delete' height='15' /></td></tr>");
}
});
});
});