在JPQL中绑定特定参数(一个)

时间:2012-01-31 08:02:35

标签: jpa-2.0 bind eclipselink jpql

在数据库中,我按列'status'分区表以获得更好的性能。我的数据库管理员问我直接在sql中输入该列的查询值(不是通过参数绑定)。

我可以通过在false上设置提示QueryHints.BIND_PARAMETERS来更改绑定,但是然后所有参数都在sql中。

我可以设置不仅仅绑定'status'参数吗?

BIND_PARAMETERS = true时的示例结果

SELECT t0.* FROM S_JOBS_ORG_UNIT_CFG t0 
WHERE ((((t0.ORG_ID = ?) AND (t0.SCHEDULER_NEXT_ACTIVATION < SYSDATE)) AND (t0.ACTIVE = ?)) 
AND NOT EXISTS (SELECT ? FROM S_JOBS t1 WHERE (((t1.ORDER_ID = t0.ORDER_ID) AND (t1.ORG_ID = t0.ORG_ID)) AND NOT ((t1.STATUS = ?)))) )
bind => [472100, Y, 1, E]

和BIND_PARAMETERS = false时的结果

SELECT t0.* FROM S_JOBS_ORG_UNIT_CFG t0 
WHERE ((((t0.ORG_ID = 472100) AND (t0.SCHEDULER_NEXT_ACTIVATION < SYSDATE)) AND (t0.ACTIVE = Y)) 
AND NOT EXISTS (SELECT 1 FROM S_JOBS t1 WHERE (((t1.ORDER_ID = t0.ORDER_ID) AND (t1.ORG_ID = t0.ORG_ID)) AND NOT ((t1.STATUS = E)))) )

代码:

        Query jobOrgUnitCfgQuery = entityManager.createQuery(
            "SELECT c FROM JobOrgUnitCfg c WHERE c.orgId = :orgId and c.schedulerNextActivation < current_timestamp and c.active = :active and " +
            " not exists (SELECT j  FROM Job j WHERE j.orderId = c.orderId and j.orgId = c.orgId and j.status <> 'E')");

    jobOrgUnitCfgQuery.setParameter("orgId", orgId);
    jobOrgUnitCfgQuery.setParameter("active", Boolean.TRUE);
    return jobOrgUnitCfgQuery.getResultList();

1 个答案:

答案 0 :(得分:0)

我认为您最好的选择就是以编程方式构建查询,就像使用硬编码状态一样,并手动转义其他参数以避免SQL注入。