Question

我想让它每3列形成一个新行。我迷路了，即使在阅读其他帖子后也无法弄清楚如何做到这一点。所以我想让它像是

图标图标图标
图标图标图标
图标图标图标
等....

foreach($sMenu as $row) {
    $sClass = ($row['id'] == $aPage['id']) ? ' class="ui-btn-active ui-btn-custom"' : ' class="ui-btn-custom"';
    $sIcon = ($row['icon'] != '') ? ' data-icon="' . $row['icon'] . '"' : '';

    $sSiteRoot = get('site-root');

    $row['url'] .= ($row['url'] == '') ? '' : '/';

    $url = $sSiteRoot . $row['url'];
    $url = str_replace('(', '%28', $url);
    $url = str_replace(')', '%29', $url);
    $url = str_replace("'", '%27', $url);
    $sNavigation2 .= '<td><img src=". $sIcon .' . $url . '"></td>';
}

Answer 1

有时，最简单的方法是让变量跟踪运行此循环的次数。例如：

$i = 0;

然后，在循环内部，只需检查数字$i是否等于2（在这种情况下）。

foreach($sMenu as $row) {

    // this is all your old code right here...

    if ($i == 2) { 
        // then add your </tr><tr> break or whatever...
        $i = 0;
    } else {
        $i++;
    }
}

然后，继续经历foreach循环。

这也可以使用modulus operator作为编写此“划线”检查的更简洁方法来完成（如此处的其他答案所示。）

Answer 2

如果计数器可被3整除，则使用modulus（％）并输出新行：

$i = 0;

foreach($sMenu as $row) {
    $i += 1;

    $sClass = ($row['id'] == $aPage['id']) ? ' class="ui-btn-active ui-btn-custom"' : ' class="ui-btn-custom"';
    $sIcon = ($row['icon'] != '') ? ' data-icon="' . $row['icon'] . '"' : '';

    $sSiteRoot = get('site-root');

    $row['url'] .= ($row['url'] == '') ? '' : '/';

    $url = $sSiteRoot . $row['url'];
    $url = str_replace('(', '%28', $url);
    $url = str_replace(')', '%29', $url);
    $url = str_replace("'", '%27', $url);
    $sNavigation2 .= '<td><img src=". $sIcon .' . $url . '"></td>';

    if( $i % 3 == 0 ) {
        $sNavigation2 .= '</tr><tr>';
    }
}

Answer 3

你可以使用＆＃34;键＆＃34;作为数组中的索引：

foreach($sMenu as $index=>$row)
{
    if(($index)%3==0){$sNavigation2 .= "<tr>";}
    //$sClass = ($row['id'] == $aPage['id']) ? ' class="ui-btn-active ui-btn-custom"' : ' class="ui-btn-custom"';
    //$sIcon = ($row['icon'] != '') ? ' data-icon="' . $row['icon'] . '"' : '';

    //$sSiteRoot = get('site-root');

    //$row['url'] .= ($row['url'] == '') ? '' : '/';

    //$url = $sSiteRoot . $row['url'];
    //$url = str_replace('(', '%28', $url);
    //$url = str_replace(')', '%29', $url);
    //$url = str_replace("'", '%27', $url);
    //$sNavigation2 .= '<td><img src=". $sIcon .' . $url . '"></td>';
    if(($index+1)%3==0){$sNavigation2 .= "</tr>";}
}
if(count($sMenu)%3 != 2){$sNavigation2 .= "</tr>";}

Answer 4

检查每三个项目的一种方法是使用the modulo operator，它会在分割时检查剩余部分。

这里有一些让你开始的伪代码：

$counter = 0;
// start the first row
$html = '<tr>';
foreach( $sMenu as $row) {
    //add an item 
    $html .= '<td>' . $row[ 'id' ] . '</td>';
    //increment the counter, which is used to keep track of the number of items
    $counter++;
    //if $counter/3 has zero as a remainder, it's divisible by three
    if( $counter % 3 === 0 ) {
       //end the row after 3 items and begin a new one
       $html .= '</tr><tr>';
    }
}
//make sure there's an ending <tr> in case it ended on an odd number of items
$html = preg_replace( '/<tr>$/gi', '', $html );
$html .= '</tr>';

PHP foreach表列

4 个答案: