我正在尝试使用PHP和GD图像库为图像添加水印。我可以使用正确的不透明度设置应用我指定的水印。
问题是我的水印本身具有透明背景。当我尝试将此水印应用于图像时,我得到一个黑色背景。
正在应用水印的图像是jpeg。这可能是问题吗?如果是这样,我如何将jpeg转换为支持透明度的格式,应用水印,然后将其转换回来?
这是我目前的代码的关键部分。
// Determine image size and type
$size = getimagesize($this->image_path);
$size_x = $size[0];
$size_y = $size[1];
$image_type = $size[2]; // This is always a JPEG
// load source image
$image = $this->ImageCreateFromType($image_type, $this->image_path);
// Determine watermark size and type
$wsize = getimagesize($watermark_path);
$watermark_x = $wsize[0];
$watermark_y = $wsize[1];
$watermark_type = $wsize[2]; // This is typically a PNG
// load watermark
$watermark = $this->ImageCreateFromType($watermark_type, $watermark_path);
$dest_x = $this->setX($size_x, $watermark_x);
$dest_y = $this->setY($size_y, $watermark_y);
imagecopymerge($image, $watermark, $dest_x, $dest_y, 0, 0, $watermark_x, $watermark_y, $this->opacity);
虽然不太相关,但这里是ImageCreateFromType函数的代码
function ImageCreateFromType($type,$filename) {
$im = null;
switch ($type) {
case 1:
$im = ImageCreateFromGif($filename);
break;
case 2:
$im = ImageCreateFromJpeg($filename);
break;
case 3:
$im = ImageCreateFromPNG($filename);
imagealphablending($im, true);
imagesavealpha($im, true);
break;
}
return $im;
}
答案 0 :(得分:1)
阅读有关imagecolortransparent()函数的信息:http://php.net/manual/en/function.imagecolortransparent.php
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