Question

我正在编写一个php代码来搜索文本文件中的不同变量....

数据在flatfile中逐行列出，数据列表的格式为：

date | time | ip | geo-location (city) | //url

数据保存为日志文件（'track-log.txt'）

我到目前为止的代码是：

$log_file = file_get_contents('track-log.txt');

$log_lines = explode(PHP_EOL, $log_file);

$log_lines = array_flip($log_lines);

unset($log_file);

这会将文本文件分解为行，然后向后翻转这些行，以便它们在数组$ log_lines [*]中列为文本文件中的最后一行，首先显示为$ log_lines [0]

我需要计算出有多少次出现的“约会”......

<..... lots of logs here .... then .....>

jan 1st 2012 | data.....
jan 1st 2012 | data ....
jan 1st 2012 | data ....
jan 1st 2012 | data ....
jan 1st 2012 | data ....
jan 2nd 2012 | data ....
jan 2nd 2012 | data ....
jan 2nd 2012 | data .... <end log>

想象一下这是日志的结尾....我想：

$count[0] = 3 // last 3x dates are the same
$count[1] = 5 // the 5x dates before that are the same

所以我可以使用

echo $count[0];

显示日志“日期”部分中最新值的数量。

我希望数组$ count [*]停止列出@ 7字符串......

$计数[0]; ......最多...... $ count [6]

将显示过去7天日志的页数

...

额外信息....日志中每行的日期格式为

sunday, january 22, 2012 | 16:14:36 | 82.**.***.*** | bolton | //page_url

日期格式始终与在每个日志行上写入每个日期的脚本相同

...

非常感谢。

Answer 1

该函数更改了键和值，并且不反转数组..

 $log_lines = array_flip($log_lines);

这样做

$log_lines = array_reverse($log_lines);

生成计数数组

$count = array();
$index = -1;
$last_date = false;
foreach ($log_lines as $lines) {
     //sunday, january 22, 2012 | 16:14:36 | 82.**.***.*** | bolton | //page_url
     list($date,) = explode("|",$lines,2); //extract date 

     if ($last_date == $date)
          $count[$index]++;
     else {
         $last_date = $date;
         $index++;
         if ($index>=7) break; // 8. Date -> break
         $count[$index] = 1;
     }
}

Answer 2

这应该是诀窍......

<?php

$log_file = file_get_contents('track-log.txt');
$log_lines = explode(PHP_EOL, $log_file);
$log_lines = array_reverse($log_lines);
unset($log_file);
$count = array();
//loop through and itterate the count array using the date as the unique key
foreach($log_lines as $line){
    //explode this so we can use the date segment as a key
    $pieces = explode('|',$line);
    if (!isset($count[$pieces[0]])){
        //break out if we've hit the cap size
        if (count($count)>=7){break;}
        $count[$pieces[0]] = 0; 
    }
    $count[$pieces[0]]++;

}
//switch to a numeric index
$count = array_values($count);

?>

Answer 3

这是解决问题的功能方法。

$lines = file('track-log.txt');

// This is a group discriminator
// It must return a 'key' which is what to group by,
// (in this case, by column 1 of the input line).
// as well as the orginal value.
function col1group($line){
    $key = trim(current(explode('|', $line, 2)));
    return array($key=>$line);
}

// $grouper is the group-descriminator function.
// we generate a new array with our keys to group by, then group them by
// key with array_merge_recursive
function array_groupby($array, $grouper) {
    return call_user_func_array('array_merge_recursive', array_map($grouper, $array));
}

//This is all lines, in file order, grouped by date.
$linesbydate = array_groupby($lines, 'col1group');

// if you want just the last seven:
$last7dates = array_slice($linesbydate, -7);
// if you want numeric keys:
$last7groups = array_values($last7dates);
// if you want them in reverse order:
$last7groupsReversed = array_reverse($last7groups);

// desired output
var_dump($last7groupsReversed);

使用您为此程序提供的示例行将输出：

array(2) {
  [0]=>
  array(3) {
    [0]=>
    string(25) "jan 2nd 2012 | data ....
"
    [1]=>
    string(25) "jan 2nd 2012 | data ....
"
    [2]=>
    string(25) "jan 2nd 2012 | data ....
"
  }
  [1]=>
  array(5) {
    [0]=>
    string(25) "jan 1st 2012 | data.....
"
    [1]=>
    string(25) "jan 1st 2012 | data ....
"
    [2]=>
    string(25) "jan 1st 2012 | data ....
"
    [3]=>
    string(25) "jan 1st 2012 | data ....
"
    [4]=>
    string(25) "jan 1st 2012 | data ....
"
  }
}

如果您需要按其他条件进行分组，可以通过创建col1group()之类的其他功能并将其传递给array_groupby()来实现。您也可以在此功能中更改行本身（例如，调用rtrim()删除换行符。）

在数组中搜索最近7次出现

3 个答案: