Question

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Collections;
using System.ComponentModel;
using System.Data;
using System.Runtime.InteropServices;
using System.Diagnostics;
using System.Threading;
using System.Windows.Forms;
using System.Drawing;


namespace TextSendKeys
{
    class Program
    {
        [DllImport("user32.dll")]
        static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);

        static void Main(string[] args)
        {
            Process[] processes = Process.GetProcessesByName("game");
            Process game1 = processes[0];


            IntPtr p = game1.MainWindowHandle;

            ShowWindow(p,1);
            SendKeys.SendWait("{DOWN}");
            Thread.Sleep(1000);
            SendKeys.SendWait("{DOWN}");



        }
    }
}

该程序可以在游戏窗口中发送两次DOWN按钮。只有当我的窗口最小化时（它正在激活窗口并完成它的工作）它才有效。如果我的窗口被激活（未最小化），则不会发生。怎么解决？

谢谢！：）

Answer 1

尝试使用SetForegroundWindow Win32 API调用而不是ShowWindow来激活游戏窗口。（来自pinvoke.net的签名。）

[DllImport("user32.dll")]
[return: MarshalAs(UnmanagedType.Bool)]
static extern bool SetForegroundWindow(IntPtr hWnd);

static void Main(string[] args)
{
    Process[] processes = Process.GetProcessesByName("game");
    Process game1 = processes[0];

    IntPtr p = game1.MainWindowHandle;

    SetForegroundWindow(p);
    SendKeys.SendWait("{DOWN}");
    Thread.Sleep(1000);
    SendKeys.SendWait("{DOWN}");
}

C＃// SendKeys.SendWait仅在进程窗口最小化时才有效

1 个答案: