Question

我最近开始使用PHP查找Web服务调用。我无法使用以下相当简单的代码段，而Web服务会返回异常。

<?php
$client = new SoapClient("http://www.webservicex.net/geoipservice.asmx?wsdl");
print($client->__soapCall("GetGeoIP", array('IP' => '83.251.30.62')));
?>

我也尝试过更简单的$client->GetGeoIP('83.251.30.62');，但它们都会产生相同的结果。

我的代码有问题吗？以下例外：

Fatal error: Uncaught SoapFault exception: [soap:Server] 
System.Web.Services.Protocols.SoapException: Server was unable to process request. --->     System.ArgumentNullException: Value cannot be null. 
Parameter name: input at System.Text.RegularExpressions.Regex.IsMatch(String input) at 
WebserviceX.Service.Adapter.IPAdapter.CheckIP(String IP) at 
WebserviceX.Service.GeoIPService.GetGeoIP(String IPAddress) --- End of inner exception 
stack trace --- in C:\Program Files (x86)\Apache Software 
Foundation\Apache2.2\htdocs\isolda\test.php:16 Stack trace: #0 C:\Program Files 
(x86)\Apache Software Foundation\Apache2.2\htdocs\isolda\test.php(16): SoapClient-
>__soapCall('GetGeoIP', Array) #1 {main} thrown in C:\Program Files (x86)\Apache 
Software Foundation\Apache2.2\htdocs\isolda\test.php on line 16

Answer 1

你应该写"IPAddress"而不是'IP'（在数组内）它会起作用。

$client = new SoapClient("http://www.webservicex.net/geoipservice.asmx?wsdl"); 

$result = $client->GetGeoIP(array("IPAddress" => "83.251.30.62")); //change was made here

echo $result->GetGeoIPResult->CountryName;

PHP SoapClient异常，我做错了什么？

1 个答案: