我该如何转换?
PHP中的2012-01-18T11:45:00+01:00
(ISO 8601)到1326883500
(unix时间戳)?
答案 0 :(得分:58)
echo date("U",strtotime('2012-01-18T11:45:00+01:00'));
答案 1 :(得分:12)
strtotime('2012-01-18T11:45:00+01:00');
// Output : 1326883500
date_format(date_timestamp_set(new DateTime(), 1326883500), 'c');
// Output : 2012-01-18T11:45:00+01:00
date_format(date_create('@'. 1326883500), 'c') . "\n";
// Output : 2012-01-18T10:45:00+00:00
date_format(date_timestamp_set(new DateTime(), 1326883500)->setTimezone(new DateTimeZone('America/New_York')), 'c');
// Output : 2012-01-18T05:45:00-05:00