我使用带有php绑定的zeromq连接到Freeswitch中的zmq模块(一个VOIP软件交换机)。
简短:我失去了活动。 长: Freeswitch中的zmq模块以c ++的形式实现为发布者。 我的PHP代码如下:
<?php
$context = new ZMQContext();
echo "connect to freeswitch zmq module...";
$sub = new ZMQSocket($context, ZMQ::SOCKET_SUB);
$sub->setSockOpt(ZMQ::SOCKOPT_SUBSCRIBE,"");
$sub->connect("tcp://192.168.20.73:5556");
$hwm = $sub->getSockOpt(ZMQ::SOCKOPT_HWM);
echo "ok.hwm: $hwm\n";
echo "looping\n";
while(1) {
$data = $sub->recv();
$d = json_decode($sub->recv(),TRUE);
$event = $d["Event-Name"];
$date = $d["Event-Date-Local"];
$ts = $d["Event-Date-Timestamp"];
$msgnr = $d["ZMQ-Msg-Cnt"];
echo "PHP: $date msg# $msgnr $ts received $event\n";
}
?>
ZMQ-Msg-Cnt是我在freeswitch中构建到zmq模块的序列号。 我可以看到每一条消息都丢失了。 tcpdump显示zmq收到消息。
我已将PHP代码转换为C,现在我能够接收每条消息。 C:
#include "zhelpers.h"
#include "cJSON.h"
int main (void)
{
void *context = zmq_init (1);
void *subscriber = zmq_socket (context, ZMQ_SUB);
zmq_connect (subscriber, "tcp://192.168.20.73:5556");
zmq_setsockopt (subscriber, ZMQ_SUBSCRIBE, "", 0);
while (1) {
char *string = s_recv (subscriber);
cJSON *root = cJSON_Parse(string);
int msgcnt = cJSON_GetObjectItem(root,"ZMQ-Msg-Cnt")->valueint;
printf("C: %s msg# %s %s received %s\n",
cJSON_GetObjectItem(root,"Event-Date-Local")->valuestring,
cJSON_GetObjectItem(root,"ZMQ-Msg-Cnt")->valuestring,
cJSON_GetObjectItem(root,"Event-Date-Timestamp")->valuestring,
cJSON_GetObjectItem(root,"Event-Name")->valuestring
);
cJSON_Delete(root);
free (string);
}
zmq_close (subscriber);
zmq_term (context);
return 0;
}
PHP代码有什么问题吗? PHP有什么技巧/必做/提示吗?
提前致谢, 杰拉尔德韦伯
答案 0 :(得分:1)
你正在调用recv
函数两次,因此它正在加载一条消息,跳过它上面的任何处理,然后加载第二条消息:
$data = $sub->recv();
// This is your first message, called in a blocking mode
$d = json_decode($sub->recv(),TRUE);
// and here's your second one, called in a non-blocking mode
将这两行改为一行:
$d = json_decode($sub->recv());