我有5张桌子。一个主要的和另外四个(它们有不同的列)。
这是我的主表(对象)的结构。
ID |类型|名字|等...
所以我想要做的是将对象与其他(obj_mobiles,obj_tablets,...)表连接,具体取决于类型字段。 我知道我应该使用动态SQL。但我无法制作程序。我认为应该看起来像这样。
SELECT objects.type into @tbl FROM objects;
PREPARE stmnt FROM "SELECT * FROM objects AS object LEFT JOIN @tbl AS info ON object.id = info.obj_id";
EXECUTE stmnt;
DEALLOCATE PREPARE stmnt;
Aslo伪代码
SELECT * FROM objects LEFT JOIN [objects.type] ON ...
任何人都可以发布程序吗?另外,我希望所有行不仅仅是1行。 感谢。
答案 0 :(得分:7)
如果您想要所有行(批量输出)而不是一次一行,则下面应该很快,并且所有行的输出都将包含所有列。
让我们将下面的内容视为表格的字段。 obj_mobiles - ID | M1 | M2 obj_tablets - ID | T1 | T2 obj_computers - ID | C1 | C2 对象 - ID |类型|名字|等,
Select objects.*, typestable.*
from (
select ID as oID, "mobile" as otype, M1, M2, NULL T1, NULL T2, NULL C1, NULL C2 from obj_mobiles
union all
select ID as oID, "tablet" as otype, NULL, NULL, T1, T2, NULL, NULL from obj_tablets
union all
select ID as oID, "computer" as otype, NULL, NULL, NULL, NULL, C1, C2 from obj_computers) as typestable
left join objects on typestable.oID = objects.ID and typestable.otype = objects.type;
+------+--------------------+----------+------+----------+------+------+------+------+------+------+
| ID | name | type | ID | type | M1 | M2 | T1 | T2 | C1 | C2 |
+------+--------------------+----------+------+----------+------+------+------+------+------+------+
| 1 | Samsung Galaxy s2 | mobile | 1 | mobile | 1 | Thin | NULL | NULL | NULL | NULL |
| 2 | Samsung Galaxy Tab | tablet | 2 | tablet | NULL | NULL | 0.98 | 10 | NULL | NULL |
| 3 | Dell Inspiron | computer | 3 | computer | NULL | NULL | NULL | NULL | 4.98 | 1000 |
+------+--------------------+----------+------+----------+------+------+------+------+------+------+
表格如下所示。
mysql> create table objects (ID int, name varchar(50), type varchar (15));
Query OK, 0 rows affected (0.05 sec)
mysql> insert into objects values (1, "Samsung Galaxy s2", "mobile"), (2, "Samsung Galaxy Tab", "tablet"), (3, "Dell Inspiron", "computer");
Query OK, 3 rows affected (0.00 sec)
Records: 3 Duplicates: 0 Warnings: 0
mysql> create table obj_mobiles (ID int, M1 int, M2 varchar(10));
Query OK, 0 rows affected (0.03 sec)
mysql> insert into obj_mobiles values (1, 0.98, "Thin");
Query OK, 1 row affected (0.00 sec)
mysql> create table obj_tablets (ID int, T1 float, T2 int(10));
Query OK, 0 rows affected (0.03 sec)
mysql> insert into obj_tablets values (2, 0.98, 10);
Query OK, 1 row affected (0.00 sec)
mysql> create table obj_computers (ID int, C1 float, C2 int(10));
Query OK, 0 rows affected (0.03 sec)
insert into obj_computers values (3, 4.98, 1000);
还要确认列的数据类型与原始列相同,结果将保存到表中,并在下面检查数据类型。
create table temp_result as
Select objects.*, typestable.*
from (
select ID as oID, "mobile" as otype, M1, M2, NULL T1, NULL T2, NULL C1, NULL C2 from obj_mobiles
union all
select ID as oID, "tablet" as otype, NULL, NULL, T1, T2, NULL, NULL from obj_tablets
union all
select ID as oID, "computer" as otype, NULL, NULL, NULL, NULL, C1, C2 from obj_computers) as typestable
left join objects on typestable.oID = objects.ID and typestable.otype = objects.type;
mysql> desc temp_result;
+-------+-------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-------+-------------+------+-----+---------+-------+
| ID | int(11) | YES | | NULL | |
| name | varchar(50) | YES | | NULL | |
| type | varchar(15) | YES | | NULL | |
| oID | int(11) | YES | | NULL | |
| otype | varchar(8) | NO | | | |
| M1 | int(11) | YES | | NULL | |
| M2 | varchar(10) | YES | | NULL | |
| T1 | float | YES | | NULL | |
| T2 | int(11) | YES | | NULL | |
| C1 | float | YES | | NULL | |
| C2 | int(11) | YES | | NULL | |
+-------+-------------+------+-----+---------+-------+
11 rows in set (0.00 sec)
答案 1 :(得分:3)
如果objects
是父表,则表示objects
。ID
是唯一对象。对?所有其他项目(手机,平板电脑,计算机)都是儿童用于对象和手机,平板电脑不能具有相同的ID。如果是这样,使用这个简单的查询就足够了 -
SELECT * FROM objects o
LEFT JOIN obj_mobiles m
ON o.id = m.ID
LEFT JOIN obj_tablets t
ON o.id = t.ID
LEFT JOIN obj_computers c
ON o.id = c.ID
将WHERE子句添加到过滤器类型,例如:WHERE o.type ='mobile'。
答案 2 :(得分:0)
使用CONCAT创建您的准备声明。 例如
@sql = CONCAT('SELECT * FROM objects AS object LEFT JOIN ', @tbl, ' AS info ON object.id = info.obj_id');
PREPARE stmnt FROM @sql;
...