Question

就像苹果计时器应用程序一样，你不能选择“0”。你必须选择至少1小时或1分钟。这是我如何格式化选择器的文本字段..

//Formats the textfield based on the pickers.
- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component {

NSString *result = [feetArray objectAtIndex:[feetPicker selectedRowInComponent:0]];

result = [result stringByAppendingFormat:@"%@ft", [feetArray objectAtIndex:[feetPicker selectedRowInComponent:1]]];
result = [result stringByAppendingFormat:@" %@", [inchArray objectAtIndex:[inchesPicker selectedRowInComponent:0]]];
result = [result stringByAppendingFormat:@"%@", [inchArray objectAtIndex:[inchesPicker selectedRowInComponent:1]]];
result = [result stringByAppendingFormat:@" %@in", [fractionArray objectAtIndex:[fractionPicker selectedRowInComponent:0]]];

RiseTextField.text = result;
}

如果他们一直选择“0”我需要什么，我希望脚在选择器上自动转到1。在我看来，我有3个采摘者。 2个组件用于英尺，2个组件用于英寸，然后1个组件用于分数。因此它显示在文本字段中，如10f 09 1 / 16in。

Answer 1

基本上你想要做的是:(假设第0行包含零值）

-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component{
    if (([feetPicker selectedRowInComponent:0] == 0)&&
        ([feetPicker selectedRowInComponent:1] == 0)&&
        ([inchesPicker selectedRowInComponent:0] == 0)&&
        ([inchesPicker selectedRowInComponent:1] == 0)&&
        ([fractionPicker selectedRowInComponent:0] == 0)){
        // All values zero
        [feetPicker selectRow:1 
                  inComponent:1 
                     animated:YES];
        return;
    }
    // Handle valid value
}

在旁注中，请考虑使用NSMutableString result。然后，您可以只调用NSString来修改您拥有的那一行，而不是每行创建一个新的[result appendFormat:@"....。

让UIPicker至少有一英尺的价值？

1 个答案: