在花时间阅读本文之前,请参阅下面的自我回答。问题是输入无效。
当我尝试解密某些字符串时,会抛出此异常:
" at System.Security.Cryptography.RijndaelManagedTransform.DecryptData(Byte[] inputBuffer, Int32 inputOffset, Int32 inputCount, Byte[]& outputBuffer, Int32 outputOffset, PaddingMode paddingMode, Boolean fLast)
at System.Security.Cryptography.RijndaelManagedTransform.TransformFinalBlock(Byte[] inputBuffer, Int32 inputOffset, Int32 inputCount)
at System.Security.Cryptography.CryptoStream.FlushFinalBlock()
at System.Security.Cryptography.CryptoStream.Dispose(Boolean disposing)
at System.IO.Stream.Close()
at System.IO.Stream.Dispose()
at EBookReader.cryptography.DecryptString(String message, String KeyString, String IVString) in C:\\Users\\XWare\\Documents\\Visual Studio 2008\\Projects\\EBookReader\\EBookReader\\cryptography.cs:line 94"
在调试中,它会抛出此行的异常:
byte[] messageBytes = Convert.FromBase64String(message);
我认为当解密的字符串太大时会出现这个问题,因为当我尝试加密和解密短字符串时,比如“你好我是X-Ware ”它工作正常
public static string DecryptString(string message, string KeyString, string IVString)
{
byte[] Key = ASCIIEncoding.UTF8.GetBytes(KeyString);
byte[] IV = ASCIIEncoding.UTF8.GetBytes(IVString);
string decrypted = null;
RijndaelManaged rj = new RijndaelManaged();
rj.BlockSize = 256;
rj.Key = Key;
rj.IV = IV;
rj.Mode = CipherMode.CBC;
rj.Padding = PaddingMode.PKCS7;
try
{
MemoryStream ms = new MemoryStream();
Encoding enc = new ASCIIEncoding();
using (CryptoStream cs = new CryptoStream(ms, rj.CreateDecryptor(Key, IV), CryptoStreamMode.Write))
{
byte[] messageBytes = Convert.FromBase64String(message);
cs.Write(messageBytes, 0, messageBytes.Length);
cs.FlushFinalBlock();
}// This is line 94
byte[] encoded = ms.ToArray();
decrypted = enc.GetString(encoded);
ms.Close();
}
catch (Exception e)
{
Console.WriteLine("An error occurred: {0}", e.Message);
}
finally
{
rj.Clear();
}
return decrypted;
}
有什么建议吗?!
P.S。我写了一条评论,向您展示第94行 //这是第94行
答案 0 :(得分:3)
FlushFinalBlock
方法仅用于刷新最后的完整或部分字节块。因此,如果您编写的块大小超过一个,则不是正确的方法调用。在尝试从内存流中读取之前,请尝试简单地关闭加密流。
要在代码的上下文中执行此操作,只需删除行cs.FlushFinalBlock()
...
答案 1 :(得分:0)
问题是我作为Base64字符串传递的字符串无效,问题只在输入文件中,这使得解密成为不可能
Thanx all