如何确定日期是否在Java中的两个日期之间?

时间:2009-05-19 14:17:51

标签: java date

如果所有三个日期都由java.util.Date的实例表示,我如何检查日期是否在两个其他日期之间?

11 个答案:

答案 0 :(得分:230)

这可能更具可读性:

Date min, max;   // assume these are set to something
Date d;          // the date in question

return d.after(min) && d.before(max);

答案 1 :(得分:111)

如果您不知道最小值/最大值的顺序

Date a, b;   // assume these are set to something
Date d;      // the date in question

return a.compareTo(d) * d.compareTo(b) > 0;

如果您希望范围包含

return a.compareTo(d) * d.compareTo(b) >= 0;

答案 2 :(得分:38)

像这样:

Date min, max;   // assume these are set to something
Date d;          // the date in question

return d.compareTo(min) >= 0 && d.compareTo(max) <= 0;

您可以使用>代替>=<而不是<=来排除端点与“之间”。

答案 3 :(得分:11)

使用Joda-Time 2.3库可以通过以下几种方法完成此操作。

一种方法是在DateTime个实例上使用简单的isBeforeisAfter方法。顺便说一句,Joda-Time中的DateTime在概念上类似于java.util.Date(宇宙时间轴上的一个时刻),但包括一个时区。

另一种方法是在Joda-Time中构建一个Interval。 contains方法测试给定的DateTime是否在Interval所涵盖的时间范围内发生。 Interval的开头是包含的,但端点是独占的。这种方法被称为“半开放”,象征性地为[)

请参阅以下代码示例中的两种方法。

将java.util.Date实例转换为Joda-Time DateTime实例。只需将Date实例传递给DateTime的构造函数即可。在实践中,您还应该传递特定的DateTimeZone对象,而不是依赖于JVM的默认时区。

DateTime dateTime1 = new DateTime( new java.util.Date() ).minusWeeks( 1 );
DateTime dateTime2 = new DateTime( new java.util.Date() );
DateTime dateTime3 = new DateTime( new java.util.Date() ).plusWeeks( 1 );

通过测试前后比较......

boolean is1After2 = dateTime1.isAfter( dateTime2 );
boolean is2Before3 = dateTime2.isBefore( dateTime3 );

boolean is2Between1And3 = ( ( dateTime2.isAfter( dateTime1 ) ) && ( dateTime2.isBefore( dateTime3 ) ) );

使用Interval方法代替isAfter / isBefore ...

Interval interval = new Interval( dateTime1, dateTime3 );
boolean intervalContainsDateTime2 = interval.contains( dateTime2 );

转储到控制台...

System.out.println( "DateTimes: " + dateTime1 + " " + dateTime1 + " " + dateTime1 );
System.out.println( "is1After2 " + is1After2 );
System.out.println( "is2Before3 " + is2Before3 );
System.out.println( "is2Between1And3 " + is2Between1And3 );
System.out.println( "intervalContainsDateTime2 " + intervalContainsDateTime2 );

跑步时......

DateTimes: 2014-01-22T20:26:14.955-08:00 2014-01-22T20:26:14.955-08:00 2014-01-22T20:26:14.955-08:00
is1After2 false
is2Before3 true
is2Between1And3 true
intervalContainsDateTime2 true

答案 4 :(得分:8)

另一个选择

min.getTime() <= d.getTime() && d.getTime() <= max.getTime()

答案 5 :(得分:7)

日期之间包括终点可以写为

public static boolean isDateInBetweenIncludingEndPoints(final Date min, final Date max, final Date date){
    return !(date.before(min) || date.after(max));
}

答案 6 :(得分:2)

您可以使用getTime()并比较返回的长UTC值。

编辑,如果你确定你不必在1970年之前处理日期,不知道在这种情况下它会如何表现。

答案 7 :(得分:2)

您可能需要查看Joda Time,它是处理日期/时间的非常好的API。即使你真的不需要它来解决你当前的问题,它也一定能为你节省痛苦。

答案 8 :(得分:2)

import java.util.Date;

public class IsDateBetween {

public static void main (String[] args) {

          IsDateBetween idb=new IsDateBetween("12/05/2010"); // passing your Date
 }
 public IsDateBetween(String dd) {

       long  from=Date.parse("01/01/2000");  // From some date

       long to=Date.parse("12/12/2010");     // To Some Date

       long check=Date.parse(dd);

       int x=0;

      if((check-from)>0 && (to-check)>0)
      {
             x=1;
      }

 System.out.println ("From Date is greater Than  ToDate : "+x);
}   

}

答案 9 :(得分:2)

你走了:

public static void main(String[] args) throws ParseException {

        SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");

        String oeStartDateStr = "04/01/";
        String oeEndDateStr = "11/14/";

        Calendar cal = Calendar.getInstance();
        Integer year = cal.get(Calendar.YEAR);

        oeStartDateStr = oeStartDateStr.concat(year.toString());
        oeEndDateStr = oeEndDateStr.concat(year.toString());

        Date startDate = sdf.parse(oeStartDateStr);
        Date endDate = sdf.parse(oeEndDateStr);
        Date d = new Date();
        String currDt = sdf.format(d);


        if((d.after(startDate) && (d.before(endDate))) || (currDt.equals(sdf.format(startDate)) ||currDt.equals(sdf.format(endDate)))){
            System.out.println("Date is between 1st april to 14th nov...");
        }
        else{
            System.out.println("Date is not between 1st april to 14th nov...");
        }
    }

答案 10 :(得分:2)

以下是如何确定今天是否在2个月之间:

private boolean isTodayBetween(int from, int to) {
    if (from < 0 || to < 0 || from > Calendar.DECEMBER || to > Calendar.DECEMBER) {
        throw new IllegalArgumentException("Invalid month provided: from = " + from + " to = " + to);
    }
    Date now = new Date();
    GregorianCalendar cal = new GregorianCalendar();
    cal.setTime(now);
    int thisMonth = cal.get(Calendar.MONTH);
    if (from > to) {
        to = to + Calendar.DECEMBER;
        thisMonth = thisMonth + Calendar.DECEMBER;
    }
    if (thisMonth >= from && thisMonth <= to) {
        return true;
    }
    return false;
}

并称之为:

isTodayBetween(Calendar.OCTOBER, Calendar.MARCH)