Question

我需要从我的控制器获取我的'Comment'（存储在DAO中）对象并将其显示在我的JSP中，但每次我从错误块中看到错误消息。

为什么会这样，我该怎么办？

我的代码的逻辑是下一个：

点击“回复”按钮后，表格中的数据会发送到我的控制器。
Controller将数据保存在DB中并返回“Comment”实体。
我在JSP页面中得到了这个“注释”实体，并将其用于在页面上发布。

但是我从错误块中获取错误消息msg而不是成功块中的msg。

这是我的表格：

<form id="comment_${comment.getCommentId()}">
    <textarea class="textarea" rows="10" name="text"></textarea>
    <input type="hidden" name="bookId" value="${book.getBookId()}" />
    <input type="hidden" name="parentId" />
    <input type="hidden" name="commentId" value="${comment.getCommentId()}" /><br />
    <input type="button" class="button" value="Reply" id="submit_${comment.getCommentId()}" onclick="ajaxsubmit(this.id)"/>
</form>

这是我的剧本：

<script type="text/javascript">
    function ajaxsubmit(buttonId){
    var formId = document.getElementById(buttonId).parentNode.id;
    var dataString = $("#" + formId).serialize();

    $.ajax( {
        url: "ajaxcomment.htm",
        type: "post",
        data: dataString,
        dataType: "json",
        success: function(data) {
            alert(data.getCommentAdded());
        },
        error: function() {
            alert("error");
        }
    } );
}

这是我的控制器

@RequestMapping(value = "ajaxcomment.htm", method = RequestMethod.POST)
public @ResponseBody Comment ajaxcomment(
        HttpServletRequest httpServletRequest,
        @RequestParam(value = "bookId", required = false) Long bookId,
        @RequestParam(value = "parentId", required = false) Long parentId,
        @RequestParam(value = "commentId", required = false) Long commentId,
        @RequestParam(value = "text", required = true) String text) {

    String username = httpServletRequest.getRemoteUser();
    User user = userDao.getUserByUsername(username);

    Comment comment = new Comment();

    // DAO logic

    commentDao.addComment(comment);
    return comment;
}

这是我的“评论”实体：

@Entity @Table(name = "COMMENT") public class Comment implements Serializable {

@Id
@GeneratedValue
@Column(name = "COMMENT_ID", nullable = false)
private Long commentId;

@Column(name = "COMMENT_TEXT", length = 512, nullable = true)
private String commentText;

@Column(name = "COMMENT_ADDED", length = 128, nullable = true)
@Temporal(TemporalType.TIMESTAMP)
private Date commentAdded;

@ManyToOne(cascade = CascadeType.REFRESH, fetch = FetchType.EAGER)
@JoinColumn(name = "BOOK_ID")
private Book book;

@ManyToOne(cascade = CascadeType.REFRESH, fetch = FetchType.EAGER)
@JoinColumn(name = "PARENT_ID")
private Comment parentComment;

@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER, mappedBy = "parentComment")
@OrderBy("commentAdded")
private Collection<Comment> subcomments;

public void setCommentText(String commentText) {
    this.commentText = commentText;
}
public String getCommentText() {
    return this.commentText;
}

// other getters and setters are public too

这是我的applicationContext.xml：

<?xml version="1.0" encoding="UTF-8"?><beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-2.5.xsd
    http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/mvc 
    http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

<mvc:annotation-driven />
<context:component-scan base-package="com.demo"/>
<context:component-scan base-package="com.demo.service"/>
<context:annotation-config />


<bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
    <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
    <property name="prefix" value="/WEB-INF/jsp/"/>
    <property name="suffix" value=".jsp"/>
</bean>

<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver"/>

<bean id="jacksonMessageConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"/>

<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
    <property name="messageConverters">
        <list>
            <ref bean="jacksonMessageConverter" />
        </list>
    </property>
</bean>

<bean id="exceptionMessageAdapter"
    class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerExceptionResolver">
    <property name="messageConverters">
        <list>
            <!-- Support JSON -->
            <ref bean="jacksonMessageConverter" />  
        </list>
    </property>
</bean>

Answer 1

可能在您的表单中，您设置的值为value="${book.getBookId()}"而不是value="${book.bookId}"。

换句话说，你必须通过引用bean中的字段名称（实体或其他）来使用表达式语言，而不是试图直接使用该字段的getter。

Answer 2

有效。

我已经更新了我的控制器方法（处理程序）：

@Autowired private DAOComment commentDao;

@RequestMapping(value = "ajaxcomment.htm", method = RequestMethod.POST)
public @ResponseBody String ajaxcomment(
    HttpServletRequest httpServletRequest,
    @RequestParam(value = "bookId", required = false) Long bookId,
    @RequestParam(value = "parentId", required = false) Long parentId,
    @RequestParam(value = "commentId", required = false) Long commentId,
    @RequestParam(value = "text", required = true) String text) {

String username = httpServletRequest.getRemoteUser();
User user = userDao.getUserByUsername(username);

Comment comment = new Comment();

// DAO logic

commentDao.addComment(comment);
return  "{\"id\":\""    + comment.getCommentId() + "\"," +
     "\"username\":\""  + comment.getUser().getUsername() + "\"," +
     "\"text\":\""      + comment.getCommentText() + "\"," +
     "\"added\":\""     + comment.getFormattedDate() + "\"}";
}

我使用\“而不是'，因为JSON.parse()不会解析像'param':'value'，"param":"value"这样的字符串。

更新了脚本：

<script type="text/javascript">
    function ajaxsubmit(buttonId, className){
        var formId = document.getElementById(buttonId).parentNode.id;
        var dataString = $("#" + formId).serialize();
        $.ajax( {
            url: "ajaxcomment.htm",
            type: "post",
            data: dataString,
            dataType: "text",
            success: function(data) {
                var response = JSON.parse(data);

                //This's it.
                alert(response.id);

            },
            error: function() {
                alert("Error has occured.");
            }
        } );
    }
</script>

jQuery post不能将实体对象作为json获取

2 个答案: