我正在尝试设置RabbitMQ rpc。我想要一个队列来监听,当它收到一条消息时,我希望它回复一个匿名队列,该队列是通过带有多条消息的reply_to头指定的。
我有以下thor任务创建一个队列,然后使用EM:Iterator将一些消息发送回使用replyt_to路由键指定的队列:
desc "start_consumer", "start the test consumer"
def start_consumer
conf = {
:host => "localhost",
:user => "guest",
:password => "guest",
:vhost => "/",
:logging => true,
:port => 5672
}
# n = 1
AMQP.start(conf) do |connection|
channel = AMQP::Channel.new(connection)
requests_queue = channel.queue("one")
requests_queue.purge
Signal.trap("INT") do
connection.close do
EM.stop{exit}
end
end
channel.prefetch(1)
requests_queue.subscribe(:ack => true) do |header, body|
url_search = MultiJson.decode(body)
EM::Iterator.new(0..5).each do |n, iter|
lead = get_lead(n, (n == 5))
puts "about to publish #{n} message is_last = #{lead.is_last} at #{Time.now}"
AMQP::Exchange.default.publish(
MultiJson.encode(lead),
:immediate => true,
:routing_key => header.reply_to,
:correlation_id => header.correlation_id
)
iter.next
end
end
puts " [x] Awaiting RPC requests"
end
end
代码beloow向上面指定的队列发送消息,并创建一个队列,用于侦听EM :: Iterator代码发送的消息。此队列的名称是第一个队列reply_to标头的路由密钥。
def publish(urlSearch, routing_key)
EM.run do
corr_id = rand(10_000_000).to_s
requests ||= Hash.new
connection = AMQP.connect(:host => "localhost")
callback_queue = AMQP::Channel.new(connection).queue("", :exclusive => false)
callback_queue.subscribe do |header, body|
lead = safe_json_decode(body)
puts "company = #{lead["company"]} is_last = #{lead["is_last"]} received at #{Time.now}"
if lead["is_last"]
puts "in exit"
connection.close do
EM.stop{exit}
end
end
end
callback_queue.append_callback(:declare) do
AMQP::Exchange.default.publish(MultiJson.encode(urlSearch), :routing_key => routing_key, :reply_to => callback_queue.name, :correlation_id => corr_id)
end
puts "initial message sent"
end
end
上面的代码可以正常工作,但有一个令人烦恼的异常。有些事情阻止EM :: Iterator代码异步执行。只有在EM :: Iterator代码完成后才会发送消息。我希望消息在每次迭代后异步发送并由匿名队列处理。目前,只有在EM :: Iterator代码完成其最后一次迭代后才会发送所有消息。
任何人都可以看到我做错了什么或建议采用不同的方法吗?我试过EM :: defer并且有相同的行为。
答案 0 :(得分:0)
启动新线程是我的问题的答案:
Thread.new do
5.times do
lead = get_lead(n, (n == 5))
puts "message #{n} is_last = #{lead.is_last} at #{Time.now}";
AMQP::Exchange.default.publish(
MultiJson.encode(lead),
:routing_key => header.reply_to,
:correlation_id => header.correlation_id
)
n += 1
sleep(2)
end
end
创建新线程会阻止EventMachine反应器被阻止,并且消息将被异步发送。