Question

例如，

在'Car'牌桌上你有'法拉利'出现4次。而'兰博基尼'和'福特'出现了4次。

如何通过SQL制作一个命令，显示“Car”中与法拉利具有相同价值/数量的所有车辆？

感谢任何帮助。

由于

Answer 1

SELECT
    Name
FROM
    Cars
GROUP BY
    Name
HAVING
    Count(Name) = (
    SELECT
        Count(*)
    FROM
        Cars
    WHERE
        Name = "Ferrari"
    )

Answer 2

这个怎么样

with a as
(
select make, count(*) tot from car
group by make
)
select * from a where a.tot = (select tot from a where make='Ferrari');

Answer 3

select brand from car
group by brand
having count(*) = (select count(*) from car where brand = 'Ferrari')

好吧，太慢......那是老板进来的： - ）

Answer 4

SELECT COUNT(make) FROM Car WHERE make = 'Ferrari'

SQL - 使用相同的值查找不同的名称

4 个答案: