我想根据android中的特定角度旋转图像,有些像指南针......
我有这个代码......它适用于drawPath() 但我想用图像替换路径和绘图的东西.. 我试图创建一个位图图像,DrawBitmapImage,但图像不像路径那样旋转。任何帮助PLease?
public void draw(Canvas canvas) {
double angle = calculateAngle(currentLongitude, currentLatitude, targetLongitude, targetLatitude);
//Correction;
angle-=90;
//Correction for azimuth
angle-=azimuth;
if((getContext() instanceof Activity) && ((Activity)getContext()).getWindowManager().getDefaultDisplay().getOrientation()==Configuration.ORIENTATION_PORTRAIT)angle-=90;
while(angle<0)angle=angle+360;
Rect rect = canvas.getClipBounds();
int height = rect.bottom-rect.top;
int width = rect.right-rect.left;
int left = rect.left;
int top = rect.top;
if(height>width){
top+=(height-width)/2;
height=width;
}
if(width>height){
left+=(width-height)/2;
width=height;
}
float centerwidth = width/2f;
float centerheight = height/2f;
Paint p = new Paint();
p.setColor(color);
p.setStyle(Paint.Style.FILL);
p.setAntiAlias(true);
float startX = left+(float)(centerwidth+Math.cos(deg2rad(angle))*width/3.0);
float startY = top+(float)(centerheight+Math.sin(deg2rad(angle))*height/3.0);
Path path = new Path();
path.moveTo(
startX,
startY);
path.lineTo(
left+(float)(centerwidth+Math.cos(deg2rad(angle+140))*width/4.0),
top+(float)(centerheight+Math.sin(deg2rad(angle+140))*height/4.0));
path.lineTo(
left+(float)centerwidth,
top+(float)centerheight
);
path.lineTo(
left+(float)(centerwidth+Math.cos(deg2rad(angle+220))*width/4.0),
top+(float)(centerheight+Math.sin(deg2rad(angle+220))*height/4.0)
);
path.lineTo(
startX,
startY
);
canvas.drawPath(path, p);
}
答案 0 :(得分:53)
使用矩阵绘制位图时可以旋转位图:
Matrix matrix = new Matrix();
matrix.setRotate(angle, imageCenterX, imageCenterY);
yourCanvas.drawBitmap(yourBitmap, matrix, null);
您也可以在绘图之前旋转画布来执行此操作:
yourCanvas.save(Canvas.MATRIX_SAVE_FLAG); //Saving the canvas and later restoring it so only this image will be rotated.
yourCanvas.rotate(-angle);
yourCanvas.drawBitmap(yourBitmap, left, top, null);
yourCanvas.restore();
选择最适合你的那个。
答案 1 :(得分:3)
您必须首先旋转画布,然后绘制您想要的任何内容。然后绘制的对象将在屏幕上显示为旋转。
canvas.rotate(45); // degrees to rotate
尝试这个好方法。
查看本教程,您将获得有关如何绘制位图以及如何旋转画布的信息
答案 2 :(得分:1)
@Reham:请看下面的示例代码,
public class bitmaptest extends Activity {
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
LinearLayout linLayout = new LinearLayout(this);
// load the origial BitMap (500 x 500 px)
Bitmap bitmapOrg = BitmapFactory.decodeResource(getResources(),
R.drawable.android);
int width = bitmapOrg.width();
int height = bitmapOrg.height();
int newWidth = 200;
int newHeight = 200;
// calculate the scale - in this case = 0.4f
float scaleWidth = ((float) newWidth) / width;
float scaleHeight = ((float) newHeight) / height;
// createa matrix for the manipulation
Matrix matrix = new Matrix();
// resize the bit map
matrix.postScale(scaleWidth, scaleHeight);
// rotate the Bitmap
matrix.postRotate(45);
// recreate the new Bitmap
Bitmap resizedBitmap = Bitmap.createBitmap(bitmapOrg, 0, 0,
width, height, matrix, true);
// make a Drawable from Bitmap to allow to set the BitMap
// to the ImageView, ImageButton or what ever
BitmapDrawable bmd = new BitmapDrawable(resizedBitmap);
ImageView imageView = new ImageView(this);
// set the Drawable on the ImageView
imageView.setImageDrawable(bmd);
// center the Image
imageView.setScaleType(ScaleType.CENTER);
// add ImageView to the Layout
linLayout.addView(imageView,
new LinearLayout.LayoutParams(
LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT
)
);
// set LinearLayout as ContentView
setContentView(linLayout);
}
}
你必须使用矩阵来旋转图像看线
matrix.postRotate(45); -
这会将图像旋转到45度
希望这能帮助你... thx
答案 3 :(得分:1)
使用以下代码。它对我有用
浮动旋转= 30.0f;
Bitmap bitmap = your bitmap
Rect rect = new Rect(100,100,bitmap.width, bitmap.height);
Matrix matrix = new Matrix();
float px = rect.exactCenterX();
float py = rect.exactCenterY();
matrix.postTranslate(-bitmap.getWidth()/2, -bitmap.getHeight()/2);
matrix.postRotate(rotation);
matrix.postTranslate(px, py);
canvas.drawBitmap(bitmap, matrix, null);
matrix.reset();
invalidate();
答案 4 :(得分:1)
这是唯一一个对我没有问题的人。
private Bitmap rotateBitmap(Bitmap bitmap, int rotationAngleDegree){
int w = bitmap.getWidth();
int h = bitmap.getHeight();
int
newW=w, newH=h;
if (rotationAngleDegree==90 || rotationAngleDegree==270){
newW = h;
newH = w;
}
Bitmap rotatedBitmap = Bitmap.createBitmap(newW,newH, bitmap.getConfig());
Canvas canvas = new Canvas(rotatedBitmap);
Rect rect = new Rect(0,0,newW, newH);
Matrix matrix = new Matrix();
float px = rect.exactCenterX();
float py = rect.exactCenterY();
matrix.postTranslate(-bitmap.getWidth()/2, -bitmap.getHeight()/2);
matrix.postRotate(rotationAngleDegree);
matrix.postTranslate(px, py);
canvas.drawBitmap(bitmap, matrix, new Paint( Paint.ANTI_ALIAS_FLAG | Paint.DITHER_FLAG | Paint.FILTER_BITMAP_FLAG ));
matrix.reset();
return rotatedBitmap;
}
答案 5 :(得分:0)
基于@Sakthi的代码,但添加缩放比例:)
Rect rect = new Rect(0,0,canvas.getWidth(), canvas.getHeight());
Matrix matrix = new Matrix();
matrix.postTranslate(-bitmap.getWidth()/2, -bitmap.getHeight()/2);
matrix.postScale(
((float)rect.width()) / bitmap.getWidth(),
((float)rect.height()) / bitmap.getHeight());
matrix.postRotate(180);
matrix.postTranslate(rect.exactCenterX(), rect.exactCenterY());
canvas.drawBitmap(bitmap, matrix, null);