Question

我有一个类似Java的Servelet http://152.252.271.12:9999/media/servlet/RequestProcessor.do

为此，我需要像这样在Querystring中传递参数 http://152.252.271.12:9999/media/servlet/RequestProcessor.do?input=abc

我需要阅读回复。

我试过这样。

        request.Method = "POST";
        request.KeepAlive = false;
        request.Credentials = CredentialCache.DefaultCredentials;

            using (StreamWriter writer = new StreamWriter(request.GetRequestStream()))
            {
                writer.Write(postData);
            }

            // Read Response.

            HttpWebResponse webresponse = (HttpWebResponse)request.GetResponse();

            using (StreamReader reader = new StreamReader(webresponse.GetResponseStream(), Encoding.Default))
            {
                result = reader.ReadToEnd();
                logtxn.LogTxn(result, "SPDCL RESPONSE");
            }

            webresponse.Close();

任何帮助表示赞赏..

Answer 1

使用WebRequest＆amp; WebResponse类。查看http://gsraj.tripod.com/dotnet/webgetpost.html了解详情。

Answer 2

我过去遇到过类似的问题，我不得不在IIS中托管一个服务，该服务接受包含请求的字符串，并返回另一个字符串，其中包含对该请求的响应。所有上述操作都需要使用HTTP POST完成。

我找到的解决方案是在IIS上托管WCF服务并将其配置为使用HTTP GET / POST协议。

另外我记得我需要使用Stream类来输入和输出数据（在这种情况下，一个简单的字符串不起作用），换句话说，我在WCF中有一个HTTP POST方法，如：

Stream GetData(Stream data);

看看这个article。

Answer 3

您可以使用WebClient类作为servlet的客户端。例如

WebClient myWebClient = new WebClient();

// Download the Web resource and save it into a data buffer.
byte[] myDataBuffer = myWebClient.DownloadData (@"http://152.252.271.12:9999/media/servlet/RequestProcessor.do?input=abc");

// Display the downloaded data.
string download = Encoding.ASCII.GetString(myDataBuffer);

现在解析结果字符串download并获取响应。

Answer 4

请找到以下代码：

 public class MyWebRequest
    {
        private WebRequest request;
        private Stream dataStream;
        private string status;
        public String Status
        {
            get
            {
                return status;
            }
            set
            {
                status = value;
            }
        }
        public MyWebRequest(string url)
        {
            // Create a request using a URL that can receive a post.
            request = WebRequest.Create(url);
        }
        public MyWebRequest(string url, string method): this(url)
        {
            if (method.Equals("GET") || method.Equals("POST"))
            {
                // Set the Method property of the request to POST.
                request.Method = method;
            }
            else
            {
                throw new Exception("Invalid Method Type");
            }
        }
        public MyWebRequest(string url, string method, string data): this(url, method)
        {
            // Create POST data and convert it to a byte array.
            string postData = data;
            byte[] byteArray = Encoding.UTF8.GetBytes(postData);
            // Set the ContentType property of the WebRequest.
            request.ContentType = "application/x-www-form-urlencoded";
            // Set the ContentLength property of the WebRequest.
            request.ContentLength = byteArray.Length;
            // Get the request stream.
            dataStream = request.GetRequestStream();
            // Write the data to the request stream.
            dataStream.Write(byteArray, 0, byteArray.Length);
            // Close the Stream object.
            dataStream.Close();
        }
        public string GetResponse()
        {
            // Get the original response.
            WebResponse response = request.GetResponse();
            this.Status = ((HttpWebResponse) response)
                .StatusDescription;
            // Get the stream containing all content returned by the requested server.
            dataStream = response.GetResponseStream();
            // Open the stream using a StreamReader for easy access.
            StreamReader reader = new StreamReader(dataStream);
            // Read the content fully up to the end.
            string responseFromServer = reader.ReadToEnd();
            // Clean up the streams.
            reader.Close();
            dataStream.Close();
            response.Close();
            return responseFromServer;
        }
    }




 //create the constructor with post type and few data
    MyWebRequest myRequest = new MyWebRequest("http://www.yourdomain.com", "POST", "a=value1&b=value2");
    //show the response string on the console screen.
    Console.WriteLine(myRequest.GetResponse());

如何在asp.net中调用Java Servelet并从中获取响应？

4 个答案: