Question

我想在表格中插入一系列值

create TEMPORARY TABLE IF NOT EXISTS currency_numbers(
    num INT
);
insert into currency_numbers(num) VALUES (1),(2),(3),(4),(5),(6),(7),(8),(9),(10);

insert into pm_transaction_type (tran_type, fixed, rate, min_by_rate, max_by_rate, round, min_amount, max_amount, country_code, valid_since, valid_till, currency)
        select 'fee.transfer_other_free', null, 0.1, 0, null, 0, null, null, "", null, null, currency_numbers.num
        from currency_numbers
        union
        select 'fee.transfer_tip_free', null, 0.3, 4, null, 5, null, null, "", null, null, currency_numbers.num
        from currency_numbers;

在这个例子中，我在2个select语句中使用union，但我想使用大约10的union。不幸的是，我收到以下错误：

Can't reopen table: 'currency_numbers'

如何编写此查询，希望每次都不必重复属性名称列表的编号？

Answer 1

这是一个临时表问题 - 您不能在同一查询中多次引用TEMPORARY表。

TEMPORARY Table Problems

作为一种解决方法，试试这个 -

SELECT t.*, c.* FROM currency_numbers c, (
  SELECT 'fee.transfer_other_free' tran_type, null fixed, 0.1 rate, 0 min_by_rate, null max_by_rate, 0 round, null min_amount, null max_amount, '' country_code, null valid_since, null valid_till
    UNION
  SELECT 'fee.transfer_tip_free', null, 0.3, 4, null, 5, null, null, '', null, null
  ) t;

...及其INSERT版本 -

INSERT INTO pm_transaction_type (tran_type, fixed, rate, min_by_rate, max_by_rate, round, min_amount, max_amount, country_code, valid_since, valid_till, currency)
  SELECT t.*, c.* FROM currency_numbers c, (
    SELECT 'fee.transfer_other_free' tran_type, null fixed, 0.1 rate, 0 min_by_rate, null max_by_rate, 0 round, null min_amount, null max_amount, '' country_code, null valid_since, null valid_till
      UNION
    SELECT 'fee.transfer_tip_free', null, 0.3, 4, null, 5, null, null, '', null, null
    ) t;

Answer 2

我没有对此进行测试，但您明白了这一点：

insert into pm_transaction_type (tran_type, fixed, rate, min_by_rate, max_by_rate, round, min_amount, max_amount, country_code, valid_since, valid_till, currency)
        select 'fee.transfer_other_free', null, 0.1, 0, null, 0, null, null, "", null, null, currency_numbers.num
        from currency_numbers cn1
        union
        select 'fee.transfer_tip_free', null, 0.3, 4, null, 5, null, null, "", null, null, currency_numbers.num
        from currency_numbers cn2;

插入一系列值（MySQL）

2 个答案: