Question

我有一些问题需要显示值，但每次重复datagridview中的值时，我都使用Microsoft Visual C＃2005和framework 2.0。

当我编程时，我发现在循环内部我需要检查重复值并计算它们，如果出现新值显示值并发送邮件，我确实通过smtp获取邮件代码，但是我需要计算和消除重复值，只留下原始单元格并更新其余部分，这是可能的，这是连接到网格的代码和数据生成我需要认真帮助这个，因为我没有'在网上找到了正确的代码，以便有效地完成这项工作。

  try
            {

                e.Result = "";

                //int count1 = 0;
                int val = 6000;

                DataTable dt = new DataTable();
                dt.Columns.Add(new DataColumn("ComputerName", typeof(String)));          //0
                dt.Columns.Add(new DataColumn("IP", typeof(String)));            //1
                dt.Columns.Add(new DataColumn("MAC", typeof(String)));       //2
                dt.Columns.Add(new DataColumn("Descubierto", typeof(String)));  

                for (int a = 1; a <= val; a++)


                {


                    counter.Text = Convert.ToString(a);
                    if (txtWorkGroupName.Text == "") return;

                    //DataTable dt = new DataTable();
                    //dt.Clear();


                        //3
                    //int i = 0;


                    try
                    {
                        // Datos del grupo WinNT://&&&&(Nombre del grupo de trabajo)
                        DirectoryEntry DomainEntry = new DirectoryEntry("WinNT://" + txtWorkGroupName.Text + "");
                        DomainEntry.Children.SchemaFilter.Add("Computer");



                        ///*************************************************
                        /// Interacting with the pcs in the domain
                        ///*************************************************

                        foreach (DirectoryEntry machine in DomainEntry.Children)
                        {

                            string strMachineName = machine.Name;
                            string strMACAddress = "";
                            IPAddress IPAddress;
                            DateTime discovered;

                            try
                            {
                                IPAddress = getIPByName(machine.Name);

                            }
                            catch
                            {
                                continue;
                            }//try/catch

                            ///*************************************************
                            /// Get Mac
                            ///*************************************************
                            strMACAddress = getMACAddress(IPAddress);

                             ///*************************************************
                            /// discovered time
                            ///*************************************************
                            discovered = DateTime.Now;


                            ///*************************************************
                            /// Add the data to the datagridview
                            ///*************************************************

                            DataRow dr = dt.NewRow();


                            dr[0] = machine.Name;
                            dr[1] = IPAddress;
                            dr[2] = strMACAddress;
                            dr[3] = Convert.ToString(discovered);
                            dt.Rows.Add(dr);



                            dgvComputers1.DataSource = dt;



                            dgvComputers1.Refresh();

                   ///Using Unique doesent work, this was one of the solutions found
                            //dt.Columns(machine.Name).Unique = true;
                            //dt.Columns(IPAddress).Unique = true;
                            //dt.Columns(strMACAddress).Unique = true;



                        }//foreach loop


                       // DataView dv = new DataView();

                       // dv = dt;

                        Thread.Sleep(2000);

                        //dt = ((DataView)this.dgvComputers1.DataSource).Table;
                        //dt.WriteXml(@"testermac.xml");




                    }//try/catch

                    catch (Exception ex)
                    {
                        {
                            MessageBox.Show(ex.Message);
                        }
                    }


                    if (backgroundWorker2.CancellationPending)
                    {
                        e.Cancel = true;
                        return;
                    }

                }

            }
            catch (NullReferenceException ex)
            {
                MessageBox.Show("error:" + ex);
                //tbmessage.Text += "se ha producido un error: " + ex + Environment.NewLine;
                //tbmessage.SelectionStart = tbmessage.Text.Length;
                //tbmessage.ScrollToCaret();
            }
            catch (NoNullAllowedException ex)
            {
                MessageBox.Show("error:" + ex);
            }
            catch (AccessViolationException ex)
            {
                MessageBox.Show("error:" + ex);
            }


        }

Answer 1

每次尝试使用DataTable.Select或DataTable.Rows.Find检查重复时，而不是添加新行。如果没有重复添加新的新行，如果它已经存在则只更新其他列。

此外，您在循环的每次迭代中都设置了DataSource，您只需要执行一次。

这是一个简单的不完整示例，每秒更新一次网格，你应该能够根据你的程序调整逻辑。

    public partial class Form1 : Form
    {
        private readonly DataGridView _gridView;
        private readonly DataTable _dataTable;

        public Form1()
        {
            InitializeComponent();

            _dataTable = new DataTable();
            DataColumn computerColumn = new DataColumn("Name");
            _dataTable.Columns.Add(computerColumn);
            _dataTable.Columns.Add(new DataColumn("IP"));
            _dataTable.Columns.Add(new DataColumn("MAC"));
            _dataTable.Columns.Add(new DataColumn("Descubierto"));
            _dataTable.PrimaryKey = new [] { computerColumn };

            _gridView = new DataGridView
                            {
                                Dock = DockStyle.Fill,
                                DataSource = _dataTable
                            };
            Controls.Add(_gridView);

            System.Windows.Forms.Timer timer = new System.Windows.Forms.Timer();
            timer.Interval = 1000;
            timer.Tick += TimerTick;     
            timer.Start();
        }

        void TimerTick(object sender, EventArgs e)
        {
            DirectoryEntry domainEntry = new DirectoryEntry("WinNT://mydomain"); 
            domainEntry.Children.SchemaFilter.Add("Computer"); 

            _dataTable.BeginLoadData();

            foreach (DirectoryEntry machine in domainEntry.Children) 
            { 
                DataRow row = _dataTable.Rows.Find(machine.Name);

                if(row == null)
                {
                    row = _dataTable.NewRow();
                    row[0] = machine.Name;
                    _dataTable.Rows.Add(row);
                }

                row[3] = DateTime.Now.ToString();
            }

            _dataTable.EndLoadData();
        } 
    }

Datagridview，仅显示唯一值为Duplicate Cell Values C＃2005

1 个答案: