Question

我正在使用ksoap和j2me。我将用户名和密码传递给asp.net Web服务方法，Web服务将数据集返回给我。我的问题是我怎么能从这个ksoap响应（数据集）中获取“显示名称”元素？

<?xml version="1.0" encoding="utf-8" ?> 
    - <DataSet xmlns="http://tempuri.org/">
    - <xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" 
      xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
    - <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
    - <xs:complexType>
    - <xs:choice minOccurs="0" maxOccurs="unbounded">
    - <xs:element name="Users">
    - <xs:complexType>
    - <xs:sequence>
      <xs:element name="Userid" type="xs:string" minOccurs="0" /> 
      <xs:element name="Password" type="xs:string" minOccurs="0" /> 
      <xs:element name="DisplayName" type="xs:string" minOccurs="0" /> 
      <xs:element name="Role" type="xs:string" minOccurs="0" /> 
      <xs:element name="Status" type="xs:string" minOccurs="0" /> 
      <xs:element name="SessionId" type="xs:string" minOccurs="0" /> 
      </xs:sequence>
      </xs:complexType>
  </xs:element>
- <xs:element name="UserAccess">
- <xs:complexType>
- <xs:sequence>
  <xs:element name="Refno" type="xs:long" minOccurs="0" /> 
  <xs:element name="UserId" type="xs:string" minOccurs="0" /> 
  <xs:element name="MenuId" type="xs:string" minOccurs="0" /> 
  <xs:element name="Control" type="xs:string" minOccurs="0" /> 
  </xs:sequence>
  </xs:complexType>
  </xs:element>
  </xs:choice>
  </xs:complexType>
  </xs:element>
  </xs:schema>
  </DataSet>

Answer 1

您可以设置

envelope.implicitTypes = true

使用SoapObject方法导航Soap对象，如下所示：

SoapObject list = (SoapObject)response;

for(int i=0; i < list.getPropertyCount(); i++) {
    SoapObject obj = (SoapObject)list.getProperty(i);

j2me和ksoap如何在asp.net webservice中获取特定元素

1 个答案: