我将平面文件中的数据导入规范化表结构。我目前正在使用游标对相关表进行插入,因此我将主键插入到连接表中。我可以在SQL Server 2008 R2中以基于集合的方式执行此操作吗?
我有3个表:联系人,电话和contactPhones。运行导入后,我希望联系人表中有2个联系人,电话表中有2个联系人,contactPhones表中有2个联系人。真正的导入要复杂得多,但是让它工作将让我将游标的真正导入迁移到基于集合的解决方案。
似乎合并或输出关键字应该能够做我想要的但我无法使语法工作。
这是使用OUTPUT尝试它的代码示例。除非我无法引用import.contactId。
,否则我几乎可以使用它create table import(contactId int identity, phone varchar(50), name varchar(10))
create table contacts (contactId int identity, name varchar(50))
create table contactPhone (contactId int, phoneId int)
create table Phones (phoneId int identity, number varchar(10))
go
insert into import (phone, name)
select '1872', 'dave'
union (select '9110', 'Jordan')
insert into contacts
select name from import
insert into Phones (number)
OUTPUT import.contactId, INSERTED.phoneId into contactPhone
select phone from import
select * from contactPhone
以下是使用merge进行尝试的代码示例:
create table import(contactId int identity, phone varchar(50), name varchar(10))
create table contacts (contactId int identity, name varchar(50))
create table contactPhone (contactId int, phoneId int)
create table Phones (phoneId int identity, number varchar(10))
go
insert into import (phone, name)
select '1872', 'dave'
union (select '9110', 'Jordan')
insert into contacts
select name from import
MERGE phones target
USING (select import.contactId, import.phone, import.name
from import join contacts on import.contactId = contacts.contactId) as source
ON (target.contactId = source.contactId)
WHEN MATCHED THEN
insert into Phones (number)
OUTPUT import.contactId, INSERTED.phoneId into contactPhone
select phone from import
WHEN NOT MATCHED THEN
INSERT (name)
VALUES (source.Name)
OUTPUT INSERTED.*;
select * from contactPhone
答案 0 :(得分:2)
在merge
和contacts
上使用Phones
并将输出存储在表格变量中,以便在插入contactPhone
时使用。
insert into import (phone, name)
select '1872', 'dave' union all
select '9110', 'Jordan'
declare @ContactIDs table(SourceID int primary key, TargetID int)
declare @PhoneIDs table (SourceID int primary key, TargetID int)
merge contacts as c
using import as i
on 0 = 1
when not matched then
insert (name) values (i.name)
output i.contactId, inserted.contactId into @ContactIDs;
merge Phones as p
using import as i
on 0 = 1
when not matched then
insert (number) values (i.phone)
output i.contactId, inserted.phoneId into @PhoneIDs;
insert into contactPhone(contactId, phoneId)
select c.TargetID, p.TargetID
from import as i
inner join @ContactIDs as c
on i.contactID = c.SourceID
inner join @PhoneIDs as p
on i.contactID = p.SourceID
Using merge..output to get mapping between source.id and target.id
答案 1 :(得分:0)
你可以不合并就可以做到这一点。添加联系人和电话,然后创建与导入表匹配的联系电话关系:
insert into contacts
select name from import;
insert into Phones
select phone from import;
insert into contactPhone
select i.contactId
, p.phoneId
from import i
join phones p
on p.number = i.phone
join contacts c
on c.name = i.name;