我有以下问题,调用以下函数时将冲突初始化为NULL。
在foo结束时,冲突采用正确的值。在这个例子的情况下,*冲突应该包含值4,8和2.它根据fprintfs进行。
但是,当我在调用foo的函数中再次测试时(参见第二个代码摘录),冲突数组尚未被修改。我不知道为什么,因为我传递了一个指向数组的指针,特别是因为这种技术适用于multiDB和递归指针。任何帮助,将不胜感激。 (顺便说一句,这不是完整的代码,我只展示了相关部分)。谢谢!
int foo(
/*==================*/
uchar* buf,
uint* multiDB,
uint* recursive,
uint** conflict) {
select_consistent= conflict;
bool finished;
if (((start_of_scan == 1) && (*multiDB != 1)) || ((start_of_scan== 0) && (select_consistent == NULL))) {
fprintf(stderr, "Not doing select consistent \n ");
finished = TRUE;
}
else {
*multiDB=0;
fprintf(stderr, "Doing select consistent \n ");
finished = FALSE;
uint n;
int i = 0 ;
if (select_consistent == NULL) { /*This is the first round */
next_round = FALSE;
fp = popen("./algorithm '[t(1,[t(2,||),t(3,[t(8,||),t(10,||)])]).t(1,[t(4,||),t(6,||)]).t(1,[t(2,||),t(7,||)])]'", "r"); /* Issue the command. */
finished = FALSE;
}
if (next_round == TRUE ) {
goto parse_records;
}
fscanf(fp, "%lu", &n);
uint* conflict_ ;
if (n!=0) conflict_ = (uint*) malloc(sizeof (uint) * n);
conflict = &conflict_;
next_round = TRUE;
int j= 0 ;
while (fscanf(fp, "%lu", &n) != EOF) {
if (n == 0) {
select_consistent=conflict;
goto parse_records;
}
else {
(*conflict)[j] = n;
}
i++;
j++;
}
finished = TRUE;
}
parse_records:;
int error;
.... [other code] foo2(multiDB, recursive);
fprintf(stderr, "Array states %lu %lu \n ", (*conflict)[0], (*conflict)[1]);
fprintf(stderr, "Array states %lu %lu \n ", (*select_consistent)[0], (*select_consistent)[1]);
return error
}
调用foo的函数是这样的:
uint** conflict = NULL ;
error = foo(buf, multiDB, recursive, conflict);
fprintf(stderr, "value is %lu \n", (*conflict)[0]); //This is still unitialised.
答案 0 :(得分:0)
看起来代码有一些指针间接问题。 conflict
似乎是uint
的单维数组。如果是这样,那么初始声明应该是:
uint* conflict = NULL;
然后像这样传递:
foo( ... &conflict);
然后在foo
中按如下方式分配:
*conflict = (uint*)malloc( ... );
或者,如果您仍想使用conflict_
,请按以下方式分配:
*conflict = conflict_;