HttpWebRequest以URL结尾的URL

时间:2009-05-13 09:03:10

标签: .net httpwebrequest webrequest

当我使用WebRequest.Create(“http://abc/test。”)进行GET时,我得到404,因为根据fiddler的说法,尾随点被.NET剥离,Web服务器需要点。我该如何防止或解决它。任何解决方法都表示赞赏!

4 个答案:

答案 0 :(得分:30)

官方错误报告中的变通办法选项卡中的解决方法:

https://connect.microsoft.com/VisualStudio/feedback/details/386695/system-uri-incorrectly-strips-trailing-dots?wa=wsignin1.0#tabs

..似乎有效。基本上,在使用System.Uri之前,运行此代码以重置.NET中的静态标志:

MethodInfo getSyntax = typeof(UriParser).GetMethod("GetSyntax", System.Reflection.BindingFlags.Static | System.Reflection.BindingFlags.NonPublic);
FieldInfo flagsField = typeof(UriParser).GetField("m_Flags", System.Reflection.BindingFlags.Instance | System.Reflection.BindingFlags.NonPublic);
if (getSyntax != null && flagsField != null)
{
    foreach (string scheme in new[] { "http", "https" })
    {
        UriParser parser = (UriParser)getSyntax.Invoke(null, new object[] { scheme });
        if (parser != null)
        {
            int flagsValue = (int)flagsField.GetValue(parser);
            // Clear the CanonicalizeAsFilePath attribute
            if ((flagsValue & 0x1000000) != 0)
                flagsField.SetValue(parser, flagsValue & ~0x1000000);
        }
    }
}

证明:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Reflection;

namespace ConsoleApplication2
{
    class Program
    {
        static void Main(string[] args)
        {
            var surl = "http://x/y./z";

            var url = new Uri(surl);
            Console.WriteLine("Broken: " + url.ToString());

            MethodInfo getSyntax = typeof(UriParser).GetMethod("GetSyntax", System.Reflection.BindingFlags.Static | System.Reflection.BindingFlags.NonPublic);
            FieldInfo flagsField = typeof(UriParser).GetField("m_Flags", System.Reflection.BindingFlags.Instance | System.Reflection.BindingFlags.NonPublic);
            if (getSyntax != null && flagsField != null)
            {
                foreach (string scheme in new[] { "http", "https" })
                {
                    UriParser parser = (UriParser)getSyntax.Invoke(null, new object[] { scheme });
                    if (parser != null)
                    {
                        int flagsValue = (int)flagsField.GetValue(parser);
                        // Clear the CanonicalizeAsFilePath attribute
                        if ((flagsValue & 0x1000000) != 0)
                            flagsField.SetValue(parser, flagsValue & ~0x1000000);
                    }
                }
            }

            url = new Uri(surl);
            Console.WriteLine("Fixed: " + url.ToString());

            Console.WriteLine("Press ENTER to exit ...");
            Console.ReadLine();
        }
    }
}

答案 1 :(得分:3)

将其中一部分重写为不需要添加任何名称空间的函数

    private Uri MyUri(string url)
    {
        Uri uri = new Uri(url);
        System.Reflection.MethodInfo getSyntax = typeof(UriParser).GetMethod("GetSyntax", System.Reflection.BindingFlags.Static | System.Reflection.BindingFlags.NonPublic);
        System.Reflection.FieldInfo flagsField = typeof(UriParser).GetField("m_Flags", System.Reflection.BindingFlags.Instance | System.Reflection.BindingFlags.NonPublic);
        if (getSyntax != null && flagsField != null)
        {
            foreach (string scheme in new[] { "http", "https" })
            {
                UriParser parser = (UriParser)getSyntax.Invoke(null, new object[] { scheme });
                if (parser != null)
                {
                    int flagsValue = (int)flagsField.GetValue(parser);
                    // Clear the CanonicalizeAsFilePath attribute
                    if ((flagsValue & 0x1000000) != 0)
                        flagsField.SetValue(parser, flagsValue & ~0x1000000);
                }
            }
        }
        uri = new Uri(url);
        return uri;
    }

答案 2 :(得分:0)

这是一个已知的问题,已在微软论坛上出现过几次。

Uri类错误地认为所有URI都像Windows磁盘文件一样,其中尾随点(没有文件扩展名)不相关。

http://social.msdn.microsoft.com/Forums/en-US/netfxbcl/thread/5206beca-071f-485d-a2bd-657d635239c9/

答案 3 :(得分:-1)

您将点更改为字符串为十六进制

  string.format("{0:x2}",yoururl);

我认为它对你有用,因为我在twitter API Oauth格式化中使用它