我想在value=""
for($record_count=0;$record_count<$record;$record_count++)
{ //loop for record count
?>
<TR>
<TD CLASS="joblog-text"colspan=2 NOWRAP align="right">Invoice number or description <?php /*echo $id;*/echo $record_count; ?></TD><!--#invPrefix#-->
<TD CLASS="joblog-text"colspan=2 NOWRAP>
<INPUT TYPE="text" NAME="eg_description_<?php echo $record_count; ?>" Value="<?php
foreach ($invoice_no as $node_inv_no)
{
echo $node_inv_no->nodeValue;
}
?>" size="10">
但是文本框中的结果:
CI_INV000243005CI_INV000239562
如何将其设为第一个文本框= CI_INV000243005
第二个= CI_INV000239562
? 非常感谢
**<?php
for($record_count=0;$record_count<$record;$record_count++)
{ //loop for record count
?>
<TR>
<TD CLASS="joblog-text"colspan=2 NOWRAP align="right">Invoice number or description <?php /*echo $id;*/echo $record_count; ?></TD><!--#invPrefix#-->
<TD CLASS="joblog-text"colspan=2 NOWRAP>
<?php
foreach ($invoice_no as $node_inv_no)
{
$val = $node_inv_no->nodeValue;
echo '<INPUT TYPE="text" NAME="eg_description_' . $record_count. '" Value="' . $val . '" size="10">';
}
?>
<!-- <INPUT TYPE="text" NAME="eg_description_<?php //echo $record_count; ?>" Value="<?php //echo $node_inv_no->nodeValue;?>" size="10">-->
</TD>**
如何让它们一个接一个地显示,而不是从上到下而不是从左到右?
我想: 发票编号或说明0 = CI_INV000243005 发票编号或说明1 = CI_INV000239562
目前显示: 发票编号或说明0 = CI_INV000243005 CI_INV000239562 发票编号或说明1 = CI_INV000243005 CI_INV000239562
由于
<?php
$id=($_GET["clientID"]);
$max=($_GET["maxrecords"]);
echo "ID : ".$id."<br>";
echo "Max Records : ".$max."<br>";
$request_url = "http://10.21.13.12/solapp/documents/CINV/jadehttp.dll?SolApp&ClientID=$id&maxrecords=$max";
//$request_url = "http://10.21.13.12/solapp/documents/CINV/jadehttp.dll?SolApp&ClientID=42570935&maxrecords=100";
echo "Request URL : ".$request_url."<br>";
// Find only Posted status
$doc = new DOMDocument; // Create a new dom document
$doc->preserveWhiteSpace = false; // Set features
$doc->formatOutput = true; // Create indents on xml
$doc->Load($request_url);
$xpath = new DOMXPath($doc);
$query = '//Document/Status[. = "Posted"]/../DocumentID';
$amount_due = $xpath->query($query2); // A list of matched elements
//$query = '//Document/Status[. = "Posted"]';
$invoice_no = $xpath->query($query);
$amount_due = $xpath->query($query2); // A list of matched elements
$record =$invoice_no->length; // A list of matched elements
$invoiceArr = array();
foreach($invoice_no as $node_inv_no) {
$invoiceArr[] = $node_inv_no->nodeValue;
}
$amount_dueArr = array();
foreach ($amount_due as $node_amount_due)
{
$amount_dueArr[] = $node_amount_due->nodeValue;
}
?>
<?php for($record_count=0;$record_count<$record;$record_count++) { ?>
<TR>
<TD CLASS="joblog-text"colspan=2 NOWRAP align="right">
Invoice number or description <?php /*echo $id;*/echo $record_count; ?>
</TD>
<TD CLASS="joblog-text"colspan=2 NOWRAP>
<?php echo '<INPUT TYPE="text" NAME="eg_description_' . $record_count. '" Value="' . $invoiceArr[$record_count] . '" size="10"><br>'; ?>
</TD>
<td>
<?php echo '<INPUT TYPE="text" NAME="eg_payamt_' . $record_count. ' Value="' . $amount_dueArr[$record_count] . '" size="10"><br>'; ?>
</td>
</TR>
<?php } ?>
我想查看pay ammount:....但是它上面是空字符串, 可能是我错了循环? 有帮助吗?
非常感谢
我可以打印出$ amount_dueArr [$ record_count]:print_r($ amount_dueArr [$ record_count]);
但是:
<?php echo '<INPUT TYPE="text" NAME="eg_payamt_' . $record_count. '
Value="' . print_r($amount_dueArr[$record_count]) . '"
size="10"><br>';
显示空框,任何人都可以提供帮助吗?
应该是这样的,我忘了一个“标志
<?php echo '<INPUT TYPE="text" NAME="eg_payamt_' . $record_count. '
"Value="' . print_r($amount_dueArr[$record_count]) . '"
size="10"><br>';
答案 0 :(得分:0)
尝试这样的事情。使用以下嵌套循环。
<?php
foreach ($invoice_no as $node_inv_no) {
$val = $node_inv_no->nodeValue;
echo '<INPUT TYPE="text" NAME="eg_description_' . $record_count. '" Value="' . $val . '" size="10">';
}
?>
修改强>
<?php
$invoiceArr = array();
foreach($invoice_no as $node_inv_no) {
$invoiceArr[] = $node_inv_no->nodeValue;
}
?>
<?php for($record_count=0;$record_count<$record;$record_count++) { ?>
<TR>
<TD CLASS="joblog-text"colspan=2 NOWRAP align="right">
Invoice number or description <?php echo $record_count; ?>
</TD>
<TD CLASS="joblog-text"colspan=2 NOWRAP>
<?php echo '<INPUT TYPE="text" NAME="eg_description_' . $record_count. '" Value="' . $invoiceArr[$record_count] . '" size="10">'; ?>
</TD>
</TR>
<?php } ?>
答案 1 :(得分:0)
您可以执行以下操作,但不建议这样做。
<?php foreach ($invoice_no as $node_inv_no) { ?>
<INPUT TYPE="text" NAME="eg_description_<?php echo $record_count; ?>" Value="<?php $node_inv_no->nodeValue;?>" size="10">
<?php } ?>
This post将是进一步改进代码和逻辑处理发布数据的良好参考。 您可以将代码更改为:
<?php foreach ($invoice_no as $node_inv_no) { ?>
<INPUT TYPE="text" NAME="eg_description_<?php echo $record_count; ?>[]" Value="<?php $node_inv_no->nodeValue;?>" size="10">
<?php } ?>
在服务器端,您将获得一系列提交的值
注意:[]
代码的name
字段的结尾input
。