我需要从资产中获取位图和声音。我尝试这样做:
BitmapFactory.decodeFile("file:///android_asset/Files/Numbers/l1.png");
就像这样:
getBitmapFromAsset("Files/Numbers/l1.png");
private Bitmap getBitmapFromAsset(String strName) {
AssetManager assetManager = getAssets();
InputStream istr = null;
try {
istr = assetManager.open(strName);
} catch (IOException e) {
e.printStackTrace();
}
Bitmap bitmap = BitmapFactory.decodeStream(istr);
return bitmap;
}
但我得到的是自由空间,而不是图像。
怎么做?
答案 0 :(得分:109)
public static Bitmap getBitmapFromAsset(Context context, String filePath) {
AssetManager assetManager = context.getAssets();
InputStream istr;
Bitmap bitmap = null;
try {
istr = assetManager.open(filePath);
bitmap = BitmapFactory.decodeStream(istr);
} catch (IOException e) {
// handle exception
}
return bitmap;
}
路径只是你的文件名fx bitmap.png。如果您使用子文件夹位图/然后使用其位图/位图.png
答案 1 :(得分:13)
使用此代码正常工作
try {
InputStream bitmap=getAssets().open("icon.png");
Bitmap bit=BitmapFactory.decodeStream(bitmap);
img.setImageBitmap(bit);
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
更新
在解码Bitmap时,如果图像大小非常大,我们更经常遇到内存溢出异常。因此阅读文章How to display Image efficiently将对您有所帮助。
答案 2 :(得分:7)
接受的答案永远不会关闭InputStream
。以下是在资产文件夹中获取Bitmap
的实用程序方法:
/**
* Retrieve a bitmap from assets.
*
* @param mgr
* The {@link AssetManager} obtained via {@link Context#getAssets()}
* @param path
* The path to the asset.
* @return The {@link Bitmap} or {@code null} if we failed to decode the file.
*/
public static Bitmap getBitmapFromAsset(AssetManager mgr, String path) {
InputStream is = null;
Bitmap bitmap = null;
try {
is = mgr.open(path);
bitmap = BitmapFactory.decodeStream(is);
} catch (final IOException e) {
bitmap = null;
} finally {
if (is != null) {
try {
is.close();
} catch (IOException ignored) {
}
}
}
return bitmap;
}
答案 3 :(得分:2)
Kotlin方式,具有自动关闭输入流的功能。您必须自己处理异常。
private fun getBitmapFromAsset(context: Context, path: String): Bitmap =
context.assets.open(path).use { BitmapFactory.decodeStream(it) }
答案 4 :(得分:0)
获取存储在Assets文件夹中的图像位图的方法。
public static Bitmap getBitmapFromAssets(Context context, String fileName, int width, int height) {
AssetManager assetManager = context.getAssets();
InputStream istr;
Bitmap bitmap = null;
try {
final BitmapFactory.Options options = new BitmapFactory.Options();
options.inJustDecodeBounds = true;
istr = assetManager.open(fileName);
// Calculate inSampleSize
options.inSampleSize = calculateInSampleSize(options, width, height);
// Decode bitmap with inSampleSize set
options.inJustDecodeBounds = false;
return BitmapFactory.decodeStream(istr, null, options);
} catch (IOException e) {
Log.e("hello", "Exception: " + e.getMessage());
}
return null;
}
调整位图大小的方法。
private static int calculateInSampleSize(
BitmapFactory.Options options, int reqWidth, int reqHeight) {
// Raw height and width of image
final int height = options.outHeight;
final int width = options.outWidth;
int inSampleSize = 1;
if (height > reqHeight || width > reqWidth) {
final int halfHeight = height / 2;
final int halfWidth = width / 2;
// Calculate the largest inSampleSize value that is a power of 2 and keeps both
// height and width larger than the requested height and width.
while ((halfHeight / inSampleSize) >= reqHeight
&& (halfWidth / inSampleSize) >= reqWidth) {
inSampleSize *= 2;
}
}
return inSampleSize;
}
答案 5 :(得分:0)
简短的 Kotlin 版本:
assets
.open(name)
.use(BitmapFactory::decodeStream)