没有使用Linq to XML正确解析XML数据

时间:2011-12-09 00:58:58

标签: c# xml linq linq-to-xml

已解决 - 感谢大家的帮助!

在我开始编写代码之前,我想简单解释一下我正在努力实现的目标。我在Data文件夹中有一个XML文件,每个后代有3个元素:Month,High和Low。每个后代已经基于Month的适当顺序,但我需要将高和低字符串转换为双精度,以便我可以使用它们在图形上绘制点。这是我无法完成的部分。

到目前为止我所拥有的:

    double month = 25;
    const double temp = 275;

    string path = AppDomain.CurrentDomain.BaseDirectory + "\\Data\\";
    XDocument xmlSource;

    private void btnShowAlbany_Click(object sender, RoutedEventArgs e)
    {
        try
        {
            //Brush, Polyline, PointCollection for drawing
            SolidColorBrush myBrush = new SolidColorBrush(Color.FromArgb(255, 255, 0, 0));
            Polyline myLine = new Polyline();
            myLine.Stroke = myBrush;
            myLine.StrokeThickness = 2;
            PointCollection myPoints = new PointCollection();

            double theTemp = 0;

            //Get XML data
            xmlSource = XDocument.Load(path + @"\Albany.xml");
            var myTemps = from tmp in xmlSource.Descendants("temp")
                            select new
                            {
                                Month = tmp.Element("Month").Value,
                                High = tmp.Element("High").Value,
                                Low = tmp.Element("Low").Value
                            };

            //Pull out data for points
            foreach (var x in myTemps)
            {
                double high = Convert.ToDouble(x.High);
                double low = Convert.ToDouble(x.Low);
                theTemp = (high + low) / 2;

                myPoints.Add(new Point(month, temp - theTemp));
                month += 25;
            }

            //Add points to line, add line as child of canvas
            myLine.Points = myPoints;
            albanyCanvas.Children.Add(myLine);
        }
        catch
        {
            MessageBox.Show("Error accessing data source", "Show Temps", MessageBoxButton.OK, MessageBoxImage.Error);
        }
    }

感谢任何指导,谢谢。

(注意:我的画布网格值从25 X开始,275 Y,例如,2月的25的温度将被绘制为@ 50,250)

XML文件:

<?xml version="1.0" encoding="utf-8"?>
<Temps>
  <Temp>
    <Month>Jan</Month>
    <High>31</High>
    <Low>15</Low>
  </Temp>
  <Temp>
    <Month>Feb</Month>
    <High>35</High>
    <Low>17</Low>
  </Temp>
  <Temp>
    <Month>Mar</Month>
    <High>44</High>
    <Low>26</Low>
  </Temp>
  <Temp>
    <Month>Apr</Month>
    <High>58</High>
    <Low>37</Low>
  </Temp>
  <Temp>
    <Month>May</Month>
    <High>69</High>
    <Low>47</Low>
  </Temp>
  <Temp>
    <Month>Jun</Month>
    <High>78</High>
    <Low>57</Low>
  </Temp>
  <Temp>
    <Month>Jul</Month>
    <High>82</High>
    <Low>62</Low>
  </Temp>
  <Temp>
    <Month>Aug</Month>
    <High>80</High>
    <Low>60</Low>
  </Temp>
  <Temp>
    <Month>Sep</Month>
    <High>72</High>
    <Low>52</Low>
  </Temp>
  <Temp>
    <Month>Oct</Month>
    <High>60</High>
    <Low>40</Low>
  </Temp>
  <Temp>
    <Month>Nov</Month>
    <High>48</High>
    <Low>32</Low>
  </Temp>
  <Temp>
    <Month>Dec</Month>
    <High>36</High>
    <Low>21</Low>
  </Temp>
</Temps>

4 个答案:

答案 0 :(得分:4)

from tmp in xmlSource.Descendants("temp")是否正确?

您的XML节点称为Temp,XML是区分大小写的

您的double high = Convert.ToDouble(x.High);看起来很好,因为XML中的数据是有效的,为了安全起见,您可能会尝试类似

的内容
double high;
if (!double.TryParse(x.High, out high)) {
    // handle error
}

另外,正如其他人所指出的那样,尝试用更小的方法破解你的代码,它会更可读,更易于维护

答案 1 :(得分:3)

XML区分大小写。将您的选择器修复为.Descendants("Temp")

答案 2 :(得分:0)

你试过吗,

Convert.ToDouble(string)

答案 3 :(得分:0)

2种方式。

您可以按照上面的建议执行Convert.ToDbouble(string),但如果无法解析数字,则会抛出异常。

你可以尝试

double d;
Double.TryParse(strToParse, out d);