这是一个记忆游戏,用户选择两个按钮(单元格)。如果单元格后面的两个单词匹配,则单词保持可见,否则单元格将被隐藏,您无法看到它们后面的单词。我想要做的是让一个单元格被冻结,如果它在按下时显示它背后的单词。我想将该函数应用于choice1和choice2,甚至是用户已经找到的对。
我尝试将第16行的self.hidden = not self.hidden
更改为
if self.hidden:
self.hidden = False
else:
self.hidden = False
但这并不完美。
以下是重要部分:
from tkinter import *
import random
class Cell:
def __init__(self, word, hidden = True):
self.word = word
self.hidden = hidden
def show_word(self):
""" Shows the word behind the cell """
if self.hidden:
self.hidden = False
else:
self.hidden = False
self.button["text"] = str(self)
if mem.choice1 is None:
mem.choice1 = self
elif mem.choice2 is None:
mem.choice2 = self
mem.update_tries()
else:
choice1, choice2 = mem.choice1, mem.choice2
mem.choice1, mem.choice2 = self, None
self.check(choice1, choice2)
def check(self, choice1, choice2):
""" Checks if the chosen words are a pair """
if choice1.word != choice2.word:
for cell in (choice1, choice2):
cell.hidden = True
cell.button['text'] = str(cell)
def __str__(self):
""" Displays or hides the word """
if self.hidden:
return "---"
else:
return self.word
class Memory(Frame):
""" GUI application that creates a Memory game """
def __init__(self, master):
super(Memory, self).__init__(master)
self.grid()
self.create_widgets()
self.tries = 0
self.choice1 = None
self.choice2 = None
答案 0 :(得分:1)
您可以在不再可点击时禁用该按钮:
cell.button.config(state = DISABLED)