Question

我的mysql表的结构是：

CREATE TABLE IF NOT EXISTS `tb_hour_counts` (
  `date` date NOT NULL,
  `subid` int(20) NOT NULL,
  `unique_ids` int(20) NOT NULL,
  `total_ids` int(20) NOT NULL,
  `unique_ips` int(20) NOT NULL,
  `total_ips` int(20) NOT NULL,
  `global` int(20) NOT NULL,
  `time` text NOT NULL,
  UNIQUE KEY `ind_1` (`date`,`time`(5),`subid`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

我有一系列数据，如：

$array = array(
    '0' => array(
        'date' => '2011-10-10',
        'time' => '00:00',
        'subid' => '2',
        'unique_ids' => '588'
    ),
    '1' => array(
        'date' => '2011-10-10',
        'time' => '00:00',
        'subid' => '2',
        'unique_ips' => '3'
    ),
    '2' => array(
        'date' => '2011-10-10',
        'time' => '00:00',
        'subid' => '2',
        'total_ids' => '3995'
    ),
    '3' => array(
        'date' => '2011-10-10',
        'time' => '00:00',
        'subid' => '2',
        'total_ips' => '1000'
    ),
    '4' => array(
        'date' => '2011-10-10',
        'time' => '00:00',
        'subid' => '2',
        'global' => '1000'
    ),
    '5' => array(
        'date' => '2011-10-10',
        'time' => '01:00',
        'subid' => '3',
        'unique_ids' => '766'
    ),
    '6' => array(
        'date' => '2011-10-10',
        'time' => '01:00',
        'subid' => '3',
        'unique_ips' => '10'
    ),
    '7' => array(
        'date' => '2011-10-10',
        'time' => '01:00',
        'subid' => '3',
        'total_ids' => '934'
    ),
    '8' => array(
        'date' => '2011-10-10',
        'time' => '01:00',
        'subid' => '3',
        'total_ips' => '950'
    ),
    '9' => array(
        'date' => '2011-10-10',
        'time' => '01:00',
        'subid' => '3',
        'global' => '7554'
    )
);

目标是将数据插入表中。从此数组插入数据的结果应如下所示：

result

我相信这可以通过mysql请求，或者通过为常规插入准备数组来完成。

Answer 1

这非常混乱，但是：

// your array below
$array = array();

$newArray = array();

foreach($array as $item){
        $newArray[$item['subid']]['date'] = $item['date'];
        $item['time'] > $newArray[$item['subid']]['time'] ? $newArray[$item['subid']]['time'] = $item['time'] : null;
        $newArray[$item['subid']]['unique_ids'] += $item['unique_ids'];
        $newArray[$item['subid']]['total_ids'] += $item['total_ids'];
        $newArray[$item['subid']]['unique_ips'] += $item['unique_ips'];
        $newArray[$item['subid']]['total_ips'] += $item['total_ips'];
        $newArray[$item['subid']]['global'] += $item['global'];
}

print_r($newArray);

这会给你：

Array
(
    [2] => Array
        (
            [date] => 2011-10-10
            [time] => 00:00
            [unique_ids] => 588
            [total_ids] => 3995
            [unique_ips] => 3
            [total_ips] => 1000
            [global] => 1000
        )

    [3] => Array
        (
            [date] => 2011-10-10
            [time] => 01:00
            [unique_ids] => 766
            [total_ids] => 934
            [unique_ips] => 10
            [total_ips] => 950
            [global] => 7554
        )

)

然后您可以执行以下操作：

foreach($newArray as $key=>$value){
        echo "INSERT INTO `table` ('{$value['date']}',{$key},{$value['total_ids']})"; // etc. etc.
}

Answer 2

如果要根据日期插入，请在插入

之前使用php将数据分组到$array

Answer 3

进入数据库后，订单无关紧要。

每次检索数据的调用都会自动通过默认列对数据进行排序。

如果要从数据库中提取数据，请通过SQL查询对其进行排序。 EI。

SELECT date, subid, unique_ids, total_ids, unique_ips, total_ips, global, time FROM tb_hour_counts 
WHERE date = '2011-10-10'
ORDER BY time;

希望这有帮助。

具体的mysql插入

3 个答案: