Question

<div id="image_div">
<input type="checkbox" />
<img src="1.jpg" />
<input type="checkbox" />
<img src="2.jpg" />
<input type="checkbox" />
<img src="3.jpg" />
<input type="checkbox" />
</div>

在页面加载时，我返回一个JSON数组：

{
    "src":["lml7x8nJzI.jpg","TaR7dALIPJ.jpg","TDE2pWgIfa.jpg","tUtuDx1BEf.jpg"],
    "checked":["lml7x8nJzI.jpg","TaR7dALIPJ.jpg","tUtuDx1BEf.jpg"]
}

src包含图片的所有源名称，checked是选中的复选框类型。
checked定义检查哪个图像（每个图像都有一个复选框）。

我需要这样的最终HTML：

<div id="image_div">
<input type="checkbox" />
<img src="lml7x8nJzI.jpg" />   
<input type="checkbox" checked />              //this is a checked one
<img src="TaR7dALIPJ.jpg" />    
<input type="checkbox" checked/>                 //this is a checked one
<img src="TDE2pWgIfa.jpg" />
<input type="checkbox" />                    //this is not
<img src="tUtuDx1BEf.jpg" />     
<input type="checkbox" checked />  //this is a checked one
</div>

我可以在JavaScript中使用array contains，还是有更好的方法？

我的尝试：

var initial = "<ul class='gallary'>";
var middle = "";
var end = "</ul>";
var i;

for (i = 0; i < data.src.length; i++)
{
    if (data.checked.contains(data.src[i]))   // How can I do this?
    {
        middle = middle +
            "<li><img src=" +
            "http://localhost/project/user/" +
            "<?php echo $this->session->userdata('username');?>" +
            "/pages/" +
            "<?php echo $this->uri->segment(3);?>" +
            "/images/gallery/" +
            data.src[i] +
            " />" +
            "<br /><input type='checkbox' value=" +
            data.src[i] +
            " checked/></li>";
    }
    else
    {
        middle = middle +
            "<li><img src=" +
            "http://localhost/project/user/" +
            "<?php echo $this->session->userdata('username');?>" +
            "/pages/" +
            "<?php echo $this->uri->segment(3);?>" +
            "/images/gallery/" +
            data.src[i] +
            " />" +
            "<br /><input type='checkbox' value=" +
            data.src[i] +
            " /></li>";
    }
}

var complete = initial + middle + end;
$("#project_gallary_layout").html(complete);

Answer 1

您可以使用数组的indexOf方法

var a = ['a', 'b', 'c'];
if (a.indexOf('a') > -1 ) {
    //element is in array
} else {
    //element is not in array
}

请注意，IE6中缺少indexOf方法，但Mozilla在same page上提供了一种实现。

Answer 2

更好的方法是替换

{"src":["lml7x8nJzI.jpg","TaR7dALIPJ.jpg","TDE2pWgIfa.jpg","tUtuDx1BEf.jpg"],
 "checked":["lml7x8nJzI.jpg","TaR7dALIPJ.jpg","tUtuDx1BEf.jpg"]}

与

{"src":[
    {"src": "lml7x8nJzI.jpg", "checked": true},
    {"src": "TaR7dALIPJ.jpg", "checked": true},
    {"src": "TDE2pWgIfa.jpg", "checked": false},
    {"src": "tUtuDx1BEf.jpg", "checked": true}]
}

例如

。

然后你可以写

for(i=0;i<data.src.length;i++) {
    var elem = data.src[i];
    var checked = "";
    if (elem.checked)
        checked = "checked";
    middle = middle + 
        "<li><img src=" +
        "http://localhost/project/user/" +
        "<?php echo $this->session->userdata('username');?>" +
        "/pages/" +
        "<?php echo $this->uri->segment(3);?>" +
        "/images/gallery/" +
        elem.src +
        " />" +
        "<br /><input type='checkbox' value=" +
        elem.src +
        " " + 
        checked +
        "/></li>";
    }
}

你所做的两个字符串之间唯一不同的是属性checked（如果你想遵循标准，它应该是checked="checked"），所以我更喜欢设置一个变量{{1根据是否选中了复选框，可以输入空字符串或“选中”。

Answer 3

这是我使用indexOf的完整解决方案

$(function(){
  var url = 'http://localhost/project/user/<?php echo $this->session->userdata('username'); ?>/pages/<?php echo $this->uri->segment(3); ?>/images/gallery/'
    , complete = '<ul class="gallery">'

  data.src.forEach(function(src){
    complete += '<li><img src="' + url + src + '"><input type="checkbox" value="' + src + '"'
    if(data.checked.indexOf(src) > -1){
      complete += ' checked'
    }
    complete += '></li>'
  })

  $("#project_gallary_layout").html(complete);
})

Javascript数组包含值

3 个答案: