标准控制台输入

时间:2011-11-28 15:06:38

标签: java

下午好。

我想知道使用java的标准控制台输入的最简单方法。 当它来到int或双输入时,例如在C#中它很简单。 在java中最简单的方法是做什么?

double a;
        Console.WriteLine("Please enter the value");

        a = double.Parse(Console.ReadLine());

        Console.WriteLine("thank you for entering " + a);

亲切的问候 阿里安

5 个答案:

答案 0 :(得分:10)

直接翻译是:

Scanner scan = new Scanner(System.in);
System.out.println("Please enter the value");
double i = Double.parse(scan.nextLine());
System.out.println("thank you for entering " + i);

但您也可以使用Scanner#nextDouble()

Scanner scan = new Scanner(System.in);
System.out.println("Please enter the value");
double i = scan.nextDouble();
System.out.println("thank you for entering " + i);

答案 1 :(得分:1)

try {
      InputStreamReader isr = new InputStreamReader(System.in);
      BufferedReader br = new BufferedReader(isr);
      String s = br.readLine();
      DecimalFormat df = new DecimalFormat();
      Number n = df.parse(s);
    double d = n.doubleValue();
     } catch (IOException e) {
        e.printStackTree();
     } catch (ParseException e) {
       e.printStackTree();
     }

   try {
          InputStreamReader isr = new InputStreamReader(System.in);
          BufferedReader br = new BufferedReader(isr);
          String s = br.readLine();
          double d = Double.parseDouble(s);

        } catch (IOException e) {
         e.printStackTree();
        } catch (ParseException e) {
         e.printStackTree();
        }

答案 2 :(得分:1)

使用java.util.Scanner - 它支持从STDIN读取数字。

答案 3 :(得分:1)

JDK 5.0&上面提供了一个从控制台读取输入的功能 - Java.util.Scanner。下面的代码从控制台读取一个String和一个Integer,并将它们存储在变量中。

import java.util.Scanner;
public class InputExp {
   public static void main(String[] args) {
       String name;
       int age;
       Scanner in = new Scanner(System.in);

   // Reads a single line from the console 
   // and stores into name variable
   name = in.nextLine();

   // Reads a integer from the console
   // and stores into age variable
   age=in.nextInt();
   in.close();            

   // Prints name and age to the console
   System.out.println("Name :"+name);
  System.out.println("Age :"+age); 

} }

答案 4 :(得分:1)

试试这个

 BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
      System.out.println("Please enter the value");      
      double a = in.readDouble();
      System.console().writer().println("thank you for entering " + a);