Question

此查询返回它下面的列表，但是id会多次出现，我可以对id进行分组并将所有播放加起来，这样我就可以得到一个列表唯一ID，旁边有播放总数。这可能在sql？

SELECT [fkPlayerId],[plays]
FROM [dPlaysPerDay]
INNER JOIN dWinners
ON [dPlaysPerDay].[fkPlayerId]=dWinners.[pkWinnerId]

53693   1
53695   1
53696   1
53693   1
53692   2
53698   2
53697   1
53699   2
53698   3
53693   6
53699   2
53693   2
53700   2
53698   1

Answer 1

使用GROUP BY时，SELECT中的所有数据项都必须包含在GROUP BY中或放在Aggregate Function中。

因此，fkPlayerId应按分组，plays与SUM()函数一起使用

SELECT [fkPlayerId], SUM([plays])
FROM [dPlaysPerDay]
INNER JOIN dWinners ON [dPlaysPerDay].[fkPlayerId]=dWinners.[pkWinnerId]
GROUP BY fkPlayerId

要ORDER BY聚合函数，请为数据项指定别名，并按此顺序：

SELECT [fkPlayerId], SUM([plays]) as TotalPlays
FROM [dPlaysPerDay]
INNER JOIN dWinners ON [dPlaysPerDay].[fkPlayerId]=dWinners.[pkWinnerId]
GROUP BY fkPlayerId
ORDER BY TotalPlays

sql server分组结果

1 个答案: