Question

如何向SgmlLinkExtractor添加网址？也就是说，如何添加任意URL来运行回调？

详细说明，使用dirbot作为示例：https://github.com/scrapy/dirbot/blob/master/dirbot/spiders/googledir.py

parse_category 仅访问与SgmlLinkExtractor SgmlLinkExtractor匹配的所有内容（allow ='directory.google.com / [A-Z] [a-zA-Z _ /] + $'）

Answer 1

使用BaseSpider而不是CrawlSpider，然后设置add to start_requests或start_urls []

class MySpider(BaseSpider):
    name = "myspider"

    def start_requests(self):
        return [Request("https://www.example.com",
            callback=self.parse)]

    def parse(self, response):
        hxs = HtmlXPathSelector(response)
        ...

Answer 2

类ThemenHubSpider（CrawlSpider）：

name = 'themenHub'
allowed_domains = ['themen.t-online.de']
start_urls = ["http://themen.t-online.de/themen-a-z/a"]
rules = [Rule(SgmlLinkExtractor(allow=['id_\d+']), 'parse_news')]

Scrapy SgmlLinkExtractor添加任意URL

2 个答案: