我有员工,角色,部门域名
员工,部门具有多对一关系。
@ManyToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "fk_department_id")
private Department department;
@ManyToMany(fetch = FetchType.EAGER)
@JoinTable(name = "employee_role", joinColumns = { @JoinColumn(name = "employee_id") }, inverseJoinColumns = { @JoinColumn(name = "role_id") })
private Set<Role> roles = new HashSet<Role>(0);
- 要求:所有用户 角色管理员:
所以这就是我想要做的事情:
List<Employee> employees = getCurrentSession()
.createSQLQuery(
"select"
+ e.id as id,e.first_name as firstName,e.password as password
+ "from employee e,employee_role er,role r where e.employee_id=er.employee_id and er.role_id=r.role_id and r.name='ROLE_ADMIN' ")
.setResultTransformer(Transformers.aliasToBean(Employee.class))
.list();
问题:除了部门属性(员工表中有列fk_department_id)和角色之外,我可以像上面的查询一样轻松获取所有属性属性(有一个连接表employee_role),任何想法如何使用查询 并使用 ResultTransFormer >或者我必须在单独的查询中这样做并分别设置每个属性?