JSON结构:
{
"codes":[
{
"id":"1",
"code":{
"fname":"S",
"lname":"K",
"dateofbirth":{
"month":"12",
"day":"02",
"year":"1998"
}
}
},
{
"id":"2",
"code":{
"fname":"M",
"lname":"D",
"dateofbirth":{
"month":"10",
"day":"02",
"year":"1998"
}
}
}
]
}
我想遍历每个code
AND dateofbirth
,并在month
为12时发出提醒。如果month
为不 12,然后什么都不做。
success: function(data){
var x;
for (x = 0; x < data.codes.length; x++){
var count=0;
for (property in data.codes[x].code) {
count++;
}
}
}
如何循环浏览dateofbirth
并检查month
的值?
在“代码”下可以作为对象的多个属性的JSON结构示例。所以我想遍历code
中的所有属性并检查month
属性的值,而不是手动检查特定属性。
{
"codes":[
{
"id":"1",
"code":{
"fname":"S",
"lname":"K",
"dateofbirth":{
"month":"12",
"day":"02",
"year":"1998"
},
"membership":{
"month":"12",
"day":"12",
"year":"2011"
}
}
},
{
"id":"2",
"code":{
"fname":"M",
"lname":"D",
"dateofbirth":{
"month":"10",
"day":"02",
"year":"1998"
},
"membership":{
"month":"10",
"day":"12",
"year":"2011"
}
}
}
]
}
答案 0 :(得分:2)
mycodes=// the object from parsed JSON
for (i=0; i<mycodes.codes.length; i++) {
if (mycodes.codes[i].code.dateofbirth.month=="12") {
alert("Code " + mycodes.codes[i].id + " has birth month of 12");
}
}
顺便说一句,你真的应该把生日存储为数字,而不是字符串。