如何以编程方式检查控件时阻止触发CheckedChanged事件?
我通常按照以下方式执行此操作。
private bool isFrozen = false;
private void btn1_CheckedChanged(object sender, EventArgs e)
{
if (isFrozen)
return;
isFrozen = true;
btn2.Checked = false;
isFrozen = false;
// Do some stuff
}
private void btn2_CheckedChanged(object sender, EventArgs e)
{
if (isFrozen)
return;
isFrozen = true;
btn1.Checked = false;
isFrozen = false;
// Do another stuff
}
是否有更好或更常见的解决方案?
答案 0 :(得分:47)
我认为你的方式很好。
另一种方法是在检查之前删除EventHandler,然后在检查后再将其添加回来。这种方式消除了对isFrozen变量的需求。
private void btn1_CheckedChanged(object sender, EventArgs e)
{
btn2.CheckedChanged -= btn2_CheckedChanged;
btn2.Checked = false;
btn2.CheckedChanged += btn2_CheckedChanged;
// Do some staff
}
private void btn2_CheckedChanged(object sender, EventArgs e)
{
btn1.CheckedChanged -= btn1_CheckedChanged;
btn1.Checked = false;
btn1.CheckedChanged += btn1_CheckedChanged;
// Do another staff
}
答案 1 :(得分:7)
在VB中:
RemoveHandler btn2.CheckedChanged, AddressOf btn2_CheckedChanged
btn2.Checked = false
AddHandler btn2.CheckedChanged, AddressOf btn2_CheckedChanged
答案 2 :(得分:5)
在想要实现这样的事情一段时间后,我遇到了这篇文章。我经常使用National Instruments的Measurement Studio,以及具有事件StateChanging或StateChanged的WinForms控件传递ActionEventArgs类型的参数,该参数具有可以采用三个值的属性Action:ByKeyboard,ByMouse和Programatic。这在确定导致控件状态发生变化的原因时非常有用。我想在标准的WinForms复选框中复制它。
这是我的代码:
public enum ControlSource
{
Programatic,
ByKeyboard,
ByMouse
}
public class AwareCheckBox : Checkbox
{
public AwareCheckBox()
: base()
{
this.MouseDown += AwareCheckbox_MouseDown;
this.KeyDown += AwareCheckbox_KeyDown;
}
private ControlSource controlSource = ControlSource.Programatic;
void AwareCheckbox_KeyDown(object sender, KeyEventArgs e)
{
controlSource = ControlSource.ByKeyboard;
}
void AwareCheckbox_MouseDown(object sender, MouseEventArgs e)
{
controlSource = ControlSource.ByMouse;
}
public new event AwareControlEventHandler CheckedChanged;
protected override void OnCheckedChanged(EventArgs e)
{
var handler = CheckedChanged;
if (handler != null)
handler(this, new AwareControlEventArgs(controlSource));
controlSource = ControlSource.Programatic;
}
}
public delegate void AwareControlEventHandler(object source, AwareControlEventArgs e);
public class AwareControlEventArgs : EventArgs
{
public ControlSource Source { get; private set; }
public AwareControlEventArgs(ControlSource s)
{
Source = s;
}
}
我确信有一些改进,但我的初步测试证明它有效。我已经发布在这里,以防其他人偶然发现这个问题,并希望更清楚地区分变更的起源。欢迎任何评论。
答案 3 :(得分:0)
只需设置一个计数器值,然后在事件开始时检查该值即可。它在10分钟内解决了我的问题。我正在Xamarin中使用5个滑动按钮使其成为单选按钮。
private void testtoggle1(object sender, ToggledEventArgs e)
{
if (chk_ctr == 1) { return; }
chk_ctr = 1;
sw2.IsToggled= false;
sw3.IsToggled = false;
sw4.IsToggled = false;
sw5.IsToggled = false;
chk_ctr = 0;
}
private void testtoggle2(object sender, ToggledEventArgs e)
{
if (chk_ctr == 1) { return; }
chk_ctr = 1;
sw1.IsToggled = false;
sw3.IsToggled = false;
sw4.IsToggled = false;
sw5.IsToggled = false;
chk_ctr = 0;
}
private void testtoggle3(object sender, ToggledEventArgs e)
{
if (chk_ctr == 1) { return; }
chk_ctr = 1;
sw1.IsToggled = false;
sw2.IsToggled = false;
sw4.IsToggled = false;
sw5.IsToggled = false;
chk_ctr = 0;
}
private void testtoggle4(object sender, ToggledEventArgs e)
{
if (chk_ctr == 1) { return; }
chk_ctr = 1;
sw1.IsToggled = false;
sw2.IsToggled = false;
sw3.IsToggled = false;
sw5.IsToggled = false;
chk_ctr = 0;
}
private void testtoggle5(object sender, ToggledEventArgs e)
{
if (chk_ctr == 1) { return; }
chk_ctr = 1;
sw1.IsToggled = false;
sw2.IsToggled = false;
sw3.IsToggled = false;
sw4.IsToggled = false;
chk_ctr = 0;
}