Question

我已经开始使用故事板，iOS 5中的一个新功能，所以我开始使用选项卡式应用程序，然后我添加了一个表视图控制器并用一些虚拟数据填充单元格，现在，该表有4个单元格，现在单击每个单元格，我想打开一个newViewController，这对于每个单元格都是不同的，

所以以前，我曾经这样编码

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
   [tableView deselectRowAtIndexPath:indexPath animated:YES];

    if(indexPath.row == 0)
    {
        FirstViewController *settingsView =[[FirstViewController alloc]initWithNibName:@"FirstViewController" bundle:nil];
        [self.navigationController pushViewController:settingsView animated:YES]; 
    }
 if(indexPath.row == 1)
    {
        SecondViewController *settingsView =[[SecondViewController alloc]initWithNibName:@"SecondViewController" bundle:nil];
        [self.navigationController pushViewController:settingsView animated:YES]; 
    }
 if(indexPath.row == 2)
    {
        ThirdViewController *settingsView =[[ThirdViewController alloc]initWithNibName:@"ThirdViewController" bundle:nil];
        [self.navigationController pushViewController:settingsView animated:YES]; 
    }

}

但是知道，我该怎么做...请帮助我

谢谢＆amp;问候兰吉特

Answer 1

也许本教程可以帮到你？ http://kurrytran.blogspot.com/2011/10/ios-5-storyboard-uitableview-tutorial.html

我看到这一点（performSegueWithIdentifier：sender :)应该是从故事板中执行新viewcontroller的方法

https://developer.apple.com/library/ios/#documentation/UIKit/Reference/UIViewController_Class/Reference/Reference.html#//apple_ref/occ/instm/UIViewController/performSegueWithIdentifier:sender：

在ios 5中使用故事板的UITableViewController

1 个答案: