我是韩国人,我不擅长英语,但如果你在那里给我评论 我会很高兴,并会尝试理解它。
我创建了10个线程,并在创建后尝试加入它们并返回值 但是当我加入最后一个帖子时,我遇到了分段错误。
结果就像这样......
Before Thread 1 create
After Thread 1 create
Before Thread 0 create
After Thread 0 create
Before Thread 1 join
After Thread 1 join
Before Thread 0 join
Segmentation Fault(core dumped)
当我创建4个线程时,它就像
Before Thread 3 create
After Thread 3 create
Before Thread 2 create
After Thread 2 create
Before Thread 1 create
After Thread 1 create
Before Thread 0 create
After Thread 0 create
Before Thread 3 join
After Thread 3 join
Before Thread 2 join
After Thread 2 join
Before Thread 1 join
After Thread 1 join
Before Thread 0 join
Segmentation Fault(core dumped)
我似乎无法找到原因。
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <unistd.h>
pthread_mutex_t mutex_lock;
struct arg_struct {
int a;
int b;
};
void *t_function(void *data) {
pthread_mutex_lock(&mutex_lock);
struct arg_struct *arg = (struct arg_struct *)data;
long int s;
s = arg->a;
pthread_mutex_unlock(&mutex_lock);
return (void **)s;
}
int main()
{
int i;
pthread_t p_thread[2];
int thr_id;
int status;
struct arg_struct arg[2];
for(i = 1; i >= 0; i--) {
arg[i].a = i;
arg[i].b = i;
}
pthread_mutex_init(&mutex_lock, NULL);
for(i = 1; i >= 0; i--) {
printf("Before Thread %d create\n", i);
thr_id = pthread_create(&p_thread[i],NULL, t_function, (void *)&arg[i]);
printf("After Thread %d create\n", i);
usleep(1000);
}
int temp[2];
for(i = 1; i >= 0; i--) {
printf("Before Thread %d join\n", i);
pthread_join(p_thread[i], (void**)&status);
printf("After Thread %d join\n", i);
temp[i] = status;
}i
printf("%d%d", temp[1], temp[0]);
pthread_mutex_destroy(&mutex_lock);
return 0;
}
答案 0 :(得分:9)
pthread_t p_thread[2];
struct arg_struct arg[2];
int temp[2];
这里只为两个元素分配了空间,因此如果你启动2个以上的线程,你将会从数组的末尾运行,并可能导致堆栈崩溃或损坏。
此外:
pthread_join(p_thread[i], (void**)&status);
status
是int
,而不是void *
;尝试此操作会尝试在void *
中存储int
。在许多64位平台上,这也会溢出(因为void *
将是8个字节,而int
是4)。将status
设为void *
,然后停止尝试抛弃这样的编译器错误。他们出于某种原因是错误的。