检查互联网连接时,asynctask上的运行时错误

时间:2011-10-28 14:34:16

标签: android android-asynctask android-context runtimeexception

我在asynctask上遇到doInBackground的问题,因为我在此代码中遇到了运行时错误:

ConnectivityManager connectivity = (ConnectivityManager) content.getSystemService(Context.CONNECTIVITY_SERVICE);

((我希望看到inamgeview中的图像,但首先检查连接是否处于活动状态,这些操作是在不扩展活动的单独类中执行的)):

这是主要活动:

public class TelevideoInternationalActivity extends Activity implements OnClickListener {
/** Called when the activity is first created. */

String loc = "Nazionale";
static String home_page = "http://www.televideo.rai.it/televideo/pub/tt4web/Nazionale/16_9_page-100.png";
WorkAsyncIta wai = new WorkAsyncIta();
static String but = "";
Context content;
/************DECLARES**************/
 RelativeLayout relativeLayout1;
 ImageView imgpag;
 ProgressBar probar;
/**********INITIALIZES**************/



@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    imgpag = (ImageView)findViewById (R.id.imgpag); 
    relativeLayout1 = (RelativeLayout) findViewById(R.id.RelativeLayout1);
    probar = (ProgressBar) findViewById (R.id.probar);

    wai.execute("http://www.televideo.rai.it/televideo/pub/tt4web/Nazionale/16_9_page-100.png" );


}

private class WorkAsyncIta extends AsyncTask<String, Void, Bitmap> 
{
    @Override
    protected void onPreExecute()
    {

        probar.setVisibility(0);
    }
   @Override
   protected Bitmap  doInBackground(String... url) {

         return ItaliaTelevideo.setHomePage(url[0], content);


     }
   @Override
   protected void onPostExecute(Bitmap result) {

         probar.setVisibility(1);
         imgpag.setImageBitmap(result);
         imgpag.setScaleType(ScaleType.FIT_XY);
     }  
}

}

我已经纠正了错误,但我现在在调试视图中看到了这一点:

Thread [<17> AsyncTask #1] (Stepping)   
ThreadPoolExecutor$Worker.run() line: 672   
Thread.run() line: 1060 

并且不会在imageview上显示任何内容,如果我触摸屏幕则返回:

Thread [<3> main] (Suspended (exception IllegalStateException))
ViewRoot.handleMessage (Message) line: 1704
ViewRoot (Handler). DispatchMessage (Message) line: 99
Looper.loop () line: 123
ActivityThread.main (String []) line: 4203
Method.invokeNative (Object, Object [], Class, Class [], Class, int, boolean) line:   not available [native method]
Method.invoke (Object, Object ...) line: 521
ZygoteInit MethodAndArgsCaller.run $ () line: 791
ZygoteInit.main (String []) line: 549
NativeStart.main (String []) line: not available [native method]

2 个答案:

答案 0 :(得分:1)

content为null,因此您获得NullPointerException。您需要为content分配上下文,您可以自行分配活动,如下所示:

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    content = this; // this is the important line
    // The rest goes here...
}

答案 1 :(得分:1)

你不能在doInBackground()中做任何gui的东西,而你正在调用显示Toast消息的函数。在AsyncTask上查看documentation