我正在尝试以编程方式随时检索我的iPhone应用程序正在使用的内存量。是的我知道ObjectAlloc / Leaks。我对这些不感兴趣,只知道是否可以编写一些代码并获取正在使用的字节数并通过NSLog报告。
感谢。
答案 0 :(得分:134)
要获取应用程序正在使用的实际内存字节数,您可以执行类似下面的示例。但是,您真的应该熟悉各种分析工具,以及它们旨在让您更好地了解使用情况。
#import <mach/mach.h>
// ...
void report_memory(void) {
struct task_basic_info info;
mach_msg_type_number_t size = TASK_BASIC_INFO_COUNT;
kern_return_t kerr = task_info(mach_task_self(),
TASK_BASIC_INFO,
(task_info_t)&info,
&size);
if( kerr == KERN_SUCCESS ) {
NSLog(@"Memory in use (in bytes): %lu", info.resident_size);
NSLog(@"Memory in use (in MiB): %f", ((CGFloat)info.resident_size / 1048576));
} else {
NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
}
}
info.virtual_size结构中还有一个字段,它将为您提供可用虚拟内存的字节数(或在任何情况下分配给您的应用程序的内存作为潜在的虚拟内存)。 pgb链接到的代码将为您提供设备可用的内存量以及它的内存类型。
答案 1 :(得分:30)
TASK_BASIC_INFO
的标题说:
/* Don't use this, use MACH_TASK_BASIC_INFO instead */
以下是使用MACH_TASK_BASIC_INFO
的版本:
void report_memory(void)
{
struct mach_task_basic_info info;
mach_msg_type_number_t size = MACH_TASK_BASIC_INFO_COUNT;
kern_return_t kerr = task_info(mach_task_self(),
MACH_TASK_BASIC_INFO,
(task_info_t)&info,
&size);
if( kerr == KERN_SUCCESS ) {
NSLog(@"Memory in use (in bytes): %u", info.resident_size);
} else {
NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
}
}
答案 2 :(得分:19)
这里增强了report_memory()以快速显示NSLog()中的泄漏状态。
void report_memory(void) {
static unsigned last_resident_size=0;
static unsigned greatest = 0;
static unsigned last_greatest = 0;
struct task_basic_info info;
mach_msg_type_number_t size = sizeof(info);
kern_return_t kerr = task_info(mach_task_self(),
TASK_BASIC_INFO,
(task_info_t)&info,
&size);
if( kerr == KERN_SUCCESS ) {
int diff = (int)info.resident_size - (int)last_resident_size;
unsigned latest = info.resident_size;
if( latest > greatest ) greatest = latest; // track greatest mem usage
int greatest_diff = greatest - last_greatest;
int latest_greatest_diff = latest - greatest;
NSLog(@"Mem: %10u (%10d) : %10d : greatest: %10u (%d)", info.resident_size, diff,
latest_greatest_diff,
greatest, greatest_diff );
} else {
NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
}
last_resident_size = info.resident_size;
last_greatest = greatest;
}
答案 3 :(得分:8)
快速解决Jason Coco的回答:
func reportMemory() {
let name = mach_task_self_
let flavor = task_flavor_t(TASK_BASIC_INFO)
let basicInfo = task_basic_info()
var size: mach_msg_type_number_t = mach_msg_type_number_t(sizeofValue(basicInfo))
let pointerOfBasicInfo = UnsafeMutablePointer<task_basic_info>.alloc(1)
let kerr: kern_return_t = task_info(name, flavor, UnsafeMutablePointer(pointerOfBasicInfo), &size)
let info = pointerOfBasicInfo.move()
pointerOfBasicInfo.dealloc(1)
if kerr == KERN_SUCCESS {
print("Memory in use (in bytes): \(info.resident_size)")
} else {
print("error with task info(): \(mach_error_string(kerr))")
}
}
答案 4 :(得分:7)
已在2019年7月1日在Mojave 10.4.6的Xcode 11上进行了测试。
所有先前的答案均返回错误的结果。
这是如何获得苹果公司的奎因(Quinn)“爱斯基摩人”(The Eskimo!)所写的期望值。
这将使用phys_footprint
中的 Darwin > Mach > task_info
变量,并且与Xcode的Debug导航器中的内存条中的值紧密匹配。
返回的值以字节为单位。
https://forums.developer.apple.com/thread/105088#357415
原始代码如下。
func memoryFootprint() -> mach_vm_size_t? {
// The `TASK_VM_INFO_COUNT` and `TASK_VM_INFO_REV1_COUNT` macros are too
// complex for the Swift C importer, so we have to define them ourselves.
let TASK_VM_INFO_COUNT = mach_msg_type_number_t(MemoryLayout<task_vm_info_data_t>.size / MemoryLayout<integer_t>.size)
let TASK_VM_INFO_REV1_COUNT = mach_msg_type_number_t(MemoryLayout.offset(of: \task_vm_info_data_t.min_address)! / MemoryLayout<integer_t>.size)
var info = task_vm_info_data_t()
var count = TASK_VM_INFO_COUNT
let kr = withUnsafeMutablePointer(to: &info) { infoPtr in
infoPtr.withMemoryRebound(to: integer_t.self, capacity: Int(count)) { intPtr in
task_info(mach_task_self_, task_flavor_t(TASK_VM_INFO), intPtr, &count)
}
}
guard
kr == KERN_SUCCESS,
count >= TASK_VM_INFO_REV1_COUNT
else { return nil }
return info.phys_footprint
}
稍加修改即可创建一个类级别的Swift方法集,从而可以轻松返回实际字节和以MB为单位的格式化输出以供显示。我将其用作自动UITest套件的一部分,以记录在同一测试的多次迭代之前和之后使用的内存,以查看是否有潜在的泄漏或分配需要研究。
// Created by Alex Zavatone on 8/1/19.
//
class Memory: NSObject {
// From Quinn the Eskimo at Apple.
// https://forums.developer.apple.com/thread/105088#357415
class func memoryFootprint() -> Float? {
// The `TASK_VM_INFO_COUNT` and `TASK_VM_INFO_REV1_COUNT` macros are too
// complex for the Swift C importer, so we have to define them ourselves.
let TASK_VM_INFO_COUNT = mach_msg_type_number_t(MemoryLayout<task_vm_info_data_t>.size / MemoryLayout<integer_t>.size)
let TASK_VM_INFO_REV1_COUNT = mach_msg_type_number_t(MemoryLayout.offset(of: \task_vm_info_data_t.min_address)! / MemoryLayout<integer_t>.size)
var info = task_vm_info_data_t()
var count = TASK_VM_INFO_COUNT
let kr = withUnsafeMutablePointer(to: &info) { infoPtr in
infoPtr.withMemoryRebound(to: integer_t.self, capacity: Int(count)) { intPtr in
task_info(mach_task_self_, task_flavor_t(TASK_VM_INFO), intPtr, &count)
}
}
guard
kr == KERN_SUCCESS,
count >= TASK_VM_INFO_REV1_COUNT
else { return nil }
let usedBytes = Float(info.phys_footprint)
return usedBytes
}
class func formattedMemoryFootprint() -> String
{
let usedBytes: UInt64? = UInt64(self.memoryFootprint() ?? 0)
let usedMB = Double(usedBytes ?? 0) / 1024 / 1024
let usedMBAsString: String = "\(usedMB)MB"
return usedMBAsString
}
}
享受!
注意:进取的编码人员可能希望向该类添加静态格式化程序,以便usedMBAsString
仅返回2个有效的小数位。
答案 5 :(得分:4)
Swift 3.1 (截至2017年8月8日)
func getMemory() {
var taskInfo = mach_task_basic_info()
var count = mach_msg_type_number_t(MemoryLayout<mach_task_basic_info>.size)/4
let kerr: kern_return_t = withUnsafeMutablePointer(to: &taskInfo) {
$0.withMemoryRebound(to: integer_t.self, capacity: 1) {
task_info(mach_task_self_, task_flavor_t(MACH_TASK_BASIC_INFO), $0, &count)
}
}
if kerr == KERN_SUCCESS {
let usedMegabytes = taskInfo.resident_size/(1024*1024)
print("used megabytes: \(usedMegabytes)")
} else {
print("Error with task_info(): " +
(String(cString: mach_error_string(kerr), encoding: String.Encoding.ascii) ?? "unknown error"))
}
}
答案 6 :(得分:3)
这是一个Swift 3版本:
func mach_task_self() -> task_t {
return mach_task_self_
}
func getMegabytesUsed() -> Float? {
var info = mach_task_basic_info()
var count = mach_msg_type_number_t(MemoryLayout.size(ofValue: info) / MemoryLayout<integer_t>.size)
let kerr = withUnsafeMutablePointer(to: &info) { infoPtr in
return infoPtr.withMemoryRebound(to: integer_t.self, capacity: Int(count)) { (machPtr: UnsafeMutablePointer<integer_t>) in
return task_info(
mach_task_self(),
task_flavor_t(MACH_TASK_BASIC_INFO),
machPtr,
&count
)
}
}
guard kerr == KERN_SUCCESS else {
return nil
}
return Float(info.resident_size) / (1024 * 1024)
}
答案 7 :(得分:0)
以下是正确答案:
```
func checkVariable() {
let defaults = UserDefaults.standard
if !defaults.bool(forKey: "XXXXXX.\
(GlobalVariables.sharedinstance.circuitselectionne!)"){
titre.text = "2,90€"
} else {
titre.text = "Démarrer la visite ! "
}
}
```
答案 8 :(得分:0)
size_t memoryFootprint()
{
task_vm_info_data_t vmInfo;
mach_msg_type_number_t count = TASK_VM_INFO_COUNT;
kern_return_t result = task_info(mach_task_self(), TASK_VM_INFO, (task_info_t) &vmInfo, &count);
if (result != KERN_SUCCESS)
return 0;
return static_cast<size_t>(vmInfo.phys_footprint);
}